You want to find
P(1000 < X < 3000)
where X is normally distributed with mean 1751 and standard deviation 421. Transform X to Z, so that it follows the standard normal distribution with mean 0 and standard deviation 1 using the relation
X = 1751 + 421Z ==> Z = (X - 1751)/421
Then
P(1000 < X < 3000) = P((1000 - 1751)/421 < (X - 1751)/421 < (3000 - 1751)/421)
… ≈ P(-1.783 < Z < 2.967)
… ≈ P(Z < 2.967) - P(Z < -1.783)
… ≈ 0.9985 - 0.0373
… ≈ 0.9612
so that approximately 96.1% of the students fall in this income range.
Answer:
(9, -7)
Step-by-step explanation:
Rearrange like x and y terms next to each other, then complete the square on both.
The negative of the # numbers instead the brackets give you the centre of the circle.
Answer:
25 meters.
Step-by-step explanation:
Given in the question that,
Initial depth of the submarine = 8 meters
After the order of the captain, the submarine was made to dive another 17 meters.
So, the final cruising depth of the submarine can be calculated by <u>adding the initial depth of the submarine and the depth further increased upon the order of the captain</u>.
Thus, final cruising depth of the submarine = 8 + 17 = 25 meters.
1. You must apply the formula for calculate the volume of a cone and and the volume of a cylinder. Then, you must sum both volumes to obtain the volume on the figure attached.
2. Volume of the cone:
Vcone=1/3(πr²h)
π=3.14
r=4 mm/2
r=2 mm
h=3 mm
3. When you substitute the values above into the formula, you obtain:
<span>
Vcone=1/3(πr²h)
</span> Vcone=12.56 mm³
4. The volume of the cylinder is:
Vcylinder=<span>πr²h
</span>
π=3.14
r=4 mm/2=2 mm
h=2 mm
5. <span>When you substitute the values above into the formula, you obtain:
</span>
Vcylinder=25.12 mm³
6. The volume of the figure is:
Vt=Vcone+Vcylinder
Vt=12<span>.56 mm³+25.12 mm</span>³
Vt=37.68 mm³
