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creativ13 [48]
4 years ago
5

Write the following inequality in slope-intercept form. 6x+2y≤-46

Mathematics
1 answer:
igomit [66]4 years ago
6 0
I think its y≤-8x-23
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What 17 multiply and adds to get -2
Marrrta [24]
17 * 0 + -2.

Now we rewrite the equation and make it 17 * 0 - 2 and u get -2.
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3 years ago
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The sum of the 4 digit numbers ABCD and DCBB is a multiple of 10.
Nady [450]

The difference between the numbers ABCD and DCBB is 10000

<h3>How to determine the difference</h3>

From the information given, we have that:

  • ABCD and DCBB is a multiple of 10.
  • The digits A,B,C and D are consecutive integers
  • The number ABCD is a multiple of 3

We can say that:

B + D = 10

A = 3

B = 4

C = 5

D = 6

Now,

ABCD = 3456

DCBB = 6544

Difference between the numbers ABCD and DCBB = 3456 + 6544 = 10, 000

Thus, the difference between the numbers ABCD and DCBB is 10000

Learn more about word problems here:

brainly.com/question/13818690

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7 0
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Sonia is standing between two buildings. The building to her left is 112 feet tall and the building to her right is 78 feet tall
djverab [1.8K]

I give up on this one because it is so hard

4 0
3 years ago
colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the num
kaheart [24]
To get started, we will use the general formula for bacteria growth/decay problems:

A_{f} =  A_{i} ( e^{kt} )

where: 
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time


For doubling problems, the general formula can be shortened to:

kt = ln(2)

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
k_{1} = ln(2)/t
k_{1} = ln(2)/2 = 0.34657 per hour

Jaquan (2):
k_{2} = ln(2)/t
k_{2} = ln(2)/3 = 0.23105 per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

A_{f1} = 50( e^{0.34657(24)})
A_{f1} = 204,800

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

A_{f2} = 204,800 =  A_{i2} ( e^{0.23105(24)} )
A_{i2} = 800

3 0
3 years ago
Scatter plots and Line of Best Fit
m_a_m_a [10]
The answer will be 60+ because 48 minutes is a long time and if youstudy for a long time you memorize more
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