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Shtirlitz [24]
2 years ago
7

What is the factored form of 6x2 + 11x – 10? (2x + )( x – )

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
3 0

Answer:

6x^2+11x-10=(2x+5)(3x-2)

Step-by-step explanation:

we are given

6x^2+11x-10

We can factor it

6x^2+11x-10=6x^2+15x-4x-10

we can use grouping method

6x^2+11x-10=(6x^2+15x)-(4x+10)

now, we can take out common terms

6x^2+11x-10=3x(2x+5)-2(2x+5)

we can take 2x+5 from both terms

6x^2+11x-10=(2x+5)(3x-2)

so, we get factor terms as

6x^2+11x-10=(2x+5)(3x-2)


Klio2033 [76]2 years ago
3 0

6x^2+11x-10=6x^2+15x-4x-10=3x(2x+5)-2(2x+5)\\\\=(2x+5)(3x-2)\\\\Answer:\ \boxed{6x^2+11x-10=(2x+5)(3x-2)}

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4 0
2 years ago
SOLVED
Nastasia [14]
5)
a. The equation that describes the forces which act in the x-direction: 
<span>     Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span>     Fy = 200 * sin 30 </span>

<span>c. The x and y components of the force of tension: </span>
<span>    Tx = Fx = 200 * cos 30  </span>
<span>    Ty = Fy = 200 * sin 30 </span>

d.<span>Since desk does not budge, </span><span>frictional force = Fx
                                                                        = 200 * cos 30 </span>

<span>                                                 Normal force </span><span>= 50 * g - Fy
                                                                       = 50 g - 200 * sin 30 
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction: 
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b. The equation that describes the forces which act in the y-direction:
    F_N - (200N)sin(30) - mg = 0

c. The values of friction and normal forces will be:
     Friction force= (200N)cos(30),
     
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N

Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
4 0
3 years ago
What is ninety five hundredths in simplest fraction?
umka2103 [35]
Ninety-five hundreths is equivalent to \frac{95}{100}.

The numerator and denominator have a basic factor of 5, so we can divide the numerator and denominator by 5.

\frac{19}{20}


4 0
3 years ago
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