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Shtirlitz [24]
2 years ago
7

What is the factored form of 6x2 + 11x – 10? (2x + )( x – )

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
3 0

Answer:

6x^2+11x-10=(2x+5)(3x-2)

Step-by-step explanation:

we are given

6x^2+11x-10

We can factor it

6x^2+11x-10=6x^2+15x-4x-10

we can use grouping method

6x^2+11x-10=(6x^2+15x)-(4x+10)

now, we can take out common terms

6x^2+11x-10=3x(2x+5)-2(2x+5)

we can take 2x+5 from both terms

6x^2+11x-10=(2x+5)(3x-2)

so, we get factor terms as

6x^2+11x-10=(2x+5)(3x-2)


Klio2033 [76]2 years ago
3 0

6x^2+11x-10=6x^2+15x-4x-10=3x(2x+5)-2(2x+5)\\\\=(2x+5)(3x-2)\\\\Answer:\ \boxed{6x^2+11x-10=(2x+5)(3x-2)}

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Cuanto vale d+2c-(3a-2b) si a=2,b=-3,c=1,d=-2
kherson [118]
<h3>Solution:</h3>

given \:  \: a=2,b=-3,c=1,d=-2 \\ then \:  \: d + 2c - (3a - 2b) \\  = ( - 2) + 2(1) - (3 \times 2 - 2 \times  -3) \\  =  - 2 + 2 - (6 + 6) \\  = 0 - 12 \\  =  - 12

<h3>Answer:</h3>

-12

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3 years ago
Use the product property of roots to choose the expression equivalent to 3√5x*3√25x^2?
nignag [31]

Answer: \sqrt[3]{125x^3}.


Step-by-step explanation: Given radical expression

\sqrt[3]{5x} \times \sqrt[3]{25x^2}.

According to the product property of roots.

\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}

On applying above rule, we get

\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}

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Therefore,

\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}

<h3>So, the correct option would be second option \sqrt[3]{125x^3}.</h3>

3 0
3 years ago
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Natali [406]

Answer:

The value of x is 11

Step-by-step explanation:

<em>Two angles are complementary if the sum of their measures is 90°</em>

Let us use this rule to solve our question

∵ The angle of measure (3x)° and the angle of measure (5x + 2)°

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∴ 8x = 88

→ Divide both sides by 8 to find x

∵ 8x/8 = 88/8

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