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3 years ago

How to find the unknown variable of q-13=-13

1 answer:

7 0

You add 13 to each side of the equation.
Then the equation says ' q = 0 ', and
you immediately recognize that as its
solution.

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30 POINTS - The tables below represent the profits earned by a merchandiser from four new consignments of t-shirts. Each consign

Nuetrik [128]

The answer is the 2nd graph having a profit of 5, 15, 6, 18, and 10.
Graph 1, 3, and 4 showed a similar linear association, with the exception of graph 3 having a negative slope. In graph 2, however, the data is scattered which showed no association between the two variables.

Note: Refer to the attached pictures.

8 0

4 years ago

A baseball team played 32 games and lost 8. Katy was the catcher in 5/8 of the winning games and 1/4 of nthe losing games.

kaheart [24]

Answer:

fraction of the games did the team win is = $\frac{3}{4}$

Katy play game = 17

Step-by-step explanation:

given data

baseball team played = 32 games

lost = 8

Katy catcher = 5/8 of winning

Katy catcher = 1/4 of losing

to find out

What fraction of the games did the team win and how many games did Katy play

solution

we know total game = 32 and lost 8

so win is total - lost = 32 - 8 = 24

fraction of the games did the team win is = $\frac{\frac{24}{8} }{\frac{32}{8} }$

fraction of the games did the team win is = $\frac{3}{4}$

and

so total game 24 winning is $\frac{5}{8}$

so katy winning is $24*\frac{5}{8}$

katy winning = 3 × 5 = 15

and

losing $\frac{1}{4}$

total lose game 8

so Katy lose = 8 × $\frac{1}{4}$ = 2

Katy play game = 15 + 2 = 17

5 0

3 years ago

What is 12.9 written as a mixed number?

Elanso [62]

Answer:12 9/10

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A survey was conducted that asked 1011 people how many books they had read in the past year. results indicated that x overbarequ

Tcecarenko [31]

Since we do not know the population standard deviation, we will use the t-distribution to construct the 90% confidence interval of the mean number of books people read. The value of $t_{\frac{\alpha }{2}}$ with 1010 degrees of freedom and with alpha equals to 0.10 is 1.64

First, we need to solve for the margin of error, E.
$E=t_{\frac{\alpha }{2}}\cdot \frac{s}{\sqrt{n}}=1.64\cdot \frac{16.6}{\sqrt{1011}}=0.86$

The lower bound of the confidence interval is
$LB=\overline{x}-E=14.8-0.86=13.94$

The upper bound of the confidence interval is
$LB=\overline{x}+E=14.8+0.86=15.66$

Therefore, the 90% confidence interval is (13.94, 15.66).

We are 90% confident that the interval from 13.94 books to 15.66 books does contain the true value of the population mean number of books people read.

4 0

4 years ago

the public library has 1,845 new books and 4,527 old books. Micah puts the same number of books on 9 shelves. How many books did

baherus [9]

Answer:

708 books on each shelf!!?!!

Step-by-step explanation:

1,845 + 4,527 = 6372

6,372 ÷ 9 = 708

If I am right, please give me brainliest!!!!

- Hermionia

7 0

3 years ago