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shutvik [7]
3 years ago
15

What is 56/108? they are even numbers so they can be simplified but I don't know how to do it right.

Mathematics
2 answers:
Andrews [41]3 years ago
3 0
That answer is simplified to 7/12
Luda [366]3 years ago
3 0
Find two number that will divide evenly into both the numerator and denominator.

Let's see... I think 4 will do the trick.

56/108 / 4/4 = 14/27

14/27 is the answer.
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Blakes goes from averaging 8 hours of sleep for a school night to averaging 6.5 hours of sleep on the weekend. What is the perce
beks73 [17]

Answer:

Step-by-step explanation:

So Blakes sleep 8 hours per night during the school day

8 hours/night...................................100%

6.5 hours/night...................................?

6.5*100/8=81.25

the change in percentage is 100-81.25=18.75%

the percentage change is 18.75

if it is easier for you, another method is:

8-6.5=1.5 subtract the original amount to the new amount

1.5/8=0.1875 divide by the original amount

0.1875*100=18.75 find the percentage

7 0
3 years ago
Please help me with this question.
Rasek [7]
The answer is 4,000 ft squared because since the sides are 100 ft and 80ft then we need to multiply them which is 8,000 then divide that by 2 since it’s a triangle which is 4,000 ft squared.
6 0
3 years ago
A circular swimming pool has a radius of 15 ft. There is a path all around that pool that is three feet wide.
Romashka-Z-Leto [24]

Answer:

Circumference(C) of the circle is given by:

C = 2 \pi r

where, r is the radius of the circle.

As per the statement:

A circular swimming pool has a radius of 15 ft.

⇒radius of the pool(r) = 15 ft

There is a path all around that pool that is three feet wide.

⇒radius of the outer edge of the path around the pool(r') = 15 +3 = 18 ft

Substitute these in the formula we have;

C = 2 \pi r'

⇒C = 2 \cdot 3.14 \cdot 18 = 113.04 ft

Therefore, the circumference of the outer edge of the path around the pool is, 113.04 ft

6 0
3 years ago
Read 2 more answers
In a single growing season at the smith family orchard, the average yield per apple tree is 150 apples when the number of trees
Mariana [72]

Answer:

100 trees should be planted per acre to maximize the total yield (15000 apples per acre)

Step-by-step explanation:

<u>Functions </u>

Expressing some quantities in terms of other(s) comes in handy to understand the behavior of the situations often modeled by those functions.

Our problem tells us about the smith family orchard, where the average yield per apple tree is 150 apples when the number of trees per acre is 100 (or less). But the average yield per tree decreases when more than 100 trees are planted. The rate of decrease is 1 for each additional tree is planted

Let's call x the number of trees planted per acre in a single growing season. We have two conditions when modeling:  when x is less than 100, the average yield per apple tree (Ay) is (fixed) 150.

Ay(x)=150\ ,\ x\leqslant 100

When x is more than 100:

Ay(x)=150-x\ ,\ 100< x\leqslant 150

The upper limit is 150 because it would mean the Average yield is zero and no apples are to be harvested

Part 1

We are asked what happens if the number of trees per acre was doubled, but we don't know what the original number was. Let's make it x=60

If x=60, then we must use the first function, and

Ay(60)=150

The yield per acre will be 150*60=9000 apples

If we doubled x to 120, we would have to use the second function

Ay(120)=150-x=30

The yield per acre will be 30*120=3600 apples

Note that doubling the number of trees would make the production decrease

If we started with x=30, then  

Ay(30)=150, and we would have 150*30=4500 apples per acre

We already know that for x=60 (the double of 30), our production will be 9000 apples per acre

This shows us that in some cases, increasing the number of trees is beneficial and in other cases, it is not

Part 2

The total yield is computed as

Y(x)=x.Ay(x)

This function will be different depending on the value of x

Y(x)=150x\ ,\ x\leqslant 100

Y(x)=150x-x^2\ ,\ 100< x\leqslant 150

To find the maximum total yield we take the first derivative

Y'(x)=150\ ,\ x\leqslant 100

Y'(x)=150-2x\ ,\ 100< x\leqslant 150

The first expression has no variable, so the total yield must be evaluated in the endpoints

Y(0)=0

Y(100)=15000

Now, the second expression contains variable, it will be set to 0 to find the critical point

150-2x=0

x=75

x is outside of the boundaries, we cannot find the maximum in this interval

Answer: 100 trees should be planted per acre to maximize the total yield (15000 apples per acre)

7 0
4 years ago
Can someone just tell me which ones are correct and which ones are wrong?
lozanna [386]
First row all correct second rows all wrong and the first on of third row is correct be the last two are incorrect
6 0
3 years ago
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