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Ronch [10]
3 years ago
13

A circle has a circumference of 144π. What is the radius of the circle?

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0
To find the circumference of a circle you have to multiple the radius by 2 and also by pi. So, to find the radius when given just the circumference, who have to do the reverse operation and divide the circumference by 2 and also by pi to get the answer of 22.92993631, which you could of course round.
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Given the trinomial 2x2 − 5x + 3, what is the value of the Discriminant and what can be said about the solutions.
valina [46]
The formula to finding a discriminant would be b^2-4ac, the b value of this trinomial being -5, the a value being 2, the c value being 3. Then, you plug the values in the equation and solve: (-5)^2-4(2)(3)
This would simplify to 1, meaning there are two solutions since the discriminant value is positive. If it is 0, there is one solution, if it is negative, then there are no real solutions.
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Find the arc length of the partial circle.
Maurinko [17]

Answer:

Arc length

2\pi \times 8 \times  \frac{90}{360}  \\ 4\pi

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Sofias gym membership is $275 per year in addition to an annual locker fee of $95. What is the monthly fee?
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the equation of a circle in general form is x squared + y squared + 20x + 12 y + 15 equals 0what is the equation of the circle i
Marrrta [24]

Answer: (x+10)^2+(y+6)^2=121

Step-by-step explanation:

The equation of a circle in the general form is:

 ax^{2}+by^2+cx+dy+e=0

The equaton of  a circle in standard form is:

(x-h)^2+(y-k)^2=r^2

Where the center is at <em>(h, k)</em> and <em>r</em> is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

x^{2}+y^2+20x+12y+15=0

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

(x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121

4 0
3 years ago
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