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3 years ago

Someone answer? Please

Mathematics

2 answers:

mina [271]3 years ago

6 0

The formula for the volume of a pyramid is (1/3)area of the base x height.
And the questions gives us all the information we need! All we need to do is plug in the values.

V = 1/3 b x h
V = 1/3 x 625 x 30
V = 10 x 625
V = 6250 cubic meters

Hope this helps!

Fantom [35]3 years ago

6 0

The volume is 40 and the cubic meters was 500

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When an integer is subtracted from 5 times the next consecutive integer, the difference is 17. Find the value of the greater int

Mars2501 [29]

Answer:

Step-by-step explanation:

5(x + 1) -x = 17 Distribute the 5

5x + 5 - x = 17 Combine like terms

4x + 5 = 17 Subtract 5 from both sides

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10 months ago

Which number belongs to the solution set of the equation below?

ollegr [7]

The correct answer would be: C. 44
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2 years ago

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kolbaska11 [484]

Answer:

1,5

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2 years ago

Can you help? I'm just too lazy to answer it lol

Usimov [2.4K]

Answer:

second answer should be corr3ect tell em if wrong

Step-by-step explanation:

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2 years ago

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A truck loaded with 8000 electronic circuit boards has just pulled into a firm’s receiving dock. The supplier claims that no mor

Juliette [100K]

Answer:

The 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

Let X = number of boards that fall outside the most rigid level of industry performance specifications.

In a random sample of 300 boards the number of defective boards was 12.

Compute the sample proportion of defective boards as follows:

$\hat p =\frac{12}{300}=0.04$

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The critical value of z for 95% confidence level is,

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)$

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

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2 years ago