Answer:
4, 8, 16, 32, 64
Step-by-step explanation:
The nth term of a geometric sequence is
= a₁
Given
a₇ = 256 and a₁₀ = 2048 , then
a₁ 
= 256 → (1)
a₁ 
= 2048 → (2)
Divide (2) by (1)
= 
r³ = 8 ( take the cube root of both sides )
r = ![\sqrt[3]{8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D)
= 2
Substitute r = 2 into (1)
a₁ × 
= 256
a₁ × 64 = 256 ( divide both sides by 64 )
a₁ = 4
Then
a₁ = 4
a₂ = 2a₁ = 2 × 4 = 8
a₃ = 2a₂ = 2 × 8 = 16
a₄ = 2a₃ = 2 × 16 = 32
a₅ = 2a₄ = 2 × 32 = 64
Answer:
Bob = 6km/h, Joe = 4km/h
Step-by-step explanation:
Bob walked 6km/h after 3 hours = 18 km
Joe walked 4km/h after 3 hours = 12 km
Finally, their distance is 30 km.
The answer is, A) No solution
Answer:
Step-by-step explanation:
<u>Given </u>
<u>In the first quadrant both sine and cosine are positive, so as tangent.</u>
- tanθ = sinθ / cosθ =
θ / cosθ = 
/ 4/5 = 
/ 4/5 = - 3/5*5/4 =
- 3/4
The point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Given: k(x) = 5x - 1, h(x) = -3x - 1
We need to find the point(if any) at which these two lines k and h meets.
To find point of intersection(if any), we need to set the functions equal as at the point of intersection the (x, y) value will be same for both of the lines.
Therefore, k(x) = h(x)
=> 5x - 1 = -3x - 1
=> 8x = 0
=> x = 0
k(x=0) = 5 * 0 - 1 = -1
Hence the point at which the lines k(x) = 5x - 1 and h(x) = -3x - 1 meet is (0, -1)
Know more about "point of intersection" problems here: brainly.com/question/16929168
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