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gladu [14]
3 years ago
9

How do you write 7/8 as a fraction?

Mathematics
2 answers:
Bess [88]3 years ago
6 0
It is already as fraction. It can't be simplified
Artist 52 [7]3 years ago
5 0
7/8 is already a fraction
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Which are examples of unit rates? Check all that apply. A) 100 students for every 2 buses B) 1 teacher per 25 students C)4 penci
AleksandrR [38]

Answer:

C) 4 pencils for each student

D) 8 students per team

Step-by-step explanation:

A unit rate is the number of unit of the first type of a quantity corresponding to one unit of the second type of quantity.

That is, if a and b are two quantities,

Then, unit rate of quantity a = x units of 'a' per 1 unit of 'b' or x units of 'a' for 1 unit of 'b'

By the above statement,

The example of unit rates from the given options are,

4 pencils for each student,

8 students per team

6 0
3 years ago
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I need answers for these geometrical things<br> Yeah
Hunter-Best [27]
I really don't even know this this app literally
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7 0
2 years ago
In the number 3,394,143 the 4 in the tens place is (blank) the value of the 4 in the thousands place.
cluponka [151]

it is 0.01 times the value because it is a hundreds time smaller than the other four.

5 0
3 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?
victus00 [196]
Given the following information:

\begin{tabular}&#10;{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}&#10;\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] &#10;\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]&#10;\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\&#10;\end{tabular}
\begin{tabular}&#10;{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}&#10;\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\&#10;\end{tabular}

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\  \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\  \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}



Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\  \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\  \\ =0.00288+0.0056=\bold{0.00848}
4 0
3 years ago
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