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3 years ago

Consider the following pair of equations:

1 answer:

6 0

$3x + 3 = x - 1 \\ 3x - x = - 1 - 3 \\ 2x = - 4 \\ x = \frac{ - 4}{2 } = - 2$
Take X=-2 into y
$y = x - 1 \\ y = - 2 - 1 \\ y = - 3$
(x, y) =(-2,-3)

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My teacher never explained how to do this so can someone help me?

Natalka [10]

Answer:

75cm^2

Step-by-step explanation:

When you say a rectangular prism, it means it has the base has 4 sides of which opposite sides are equal as a rectangle. This sides substends so we have a total of 6 surfaces in this prism.

This 6 surfaces has 3 surface area the same.

The surface area = sum of area of all faces.

325= 50 + 50 + 37.5 + 37.5 + 2x; where X is the area of the surface unknown.

325= 100+ 75 + 2x

325-175= 150

150= 2x

X= 150/ 2 = 75 cm^2

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2 years ago

How did you find x? pls answer

Mariulka [41]

Answer:

x = 8 degree

Step-by-step explanation:

8x - 4 = 60 degree (being alternate interior angle)

8x = 60 + 4

8x = 64

x = 64/8

x = 8 degree

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2 years ago

Read 2 more answers

HELP ASAP

Marina CMI [18]

Answer:

sdfgfgav

Step-by-step explanation:

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2 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

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3 years ago

Is PQR = STU? if so, name which similarity postulate or theorem applies.

lutik1710 [3]

Answer:

Step-by-step explanation:

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3 years ago