Answer: y = 7.5
Step-by-step explanation:
Suppose that y varies directly with x
That is, y∝x
Convert y∝x to a full equation by introducing a constant k to the right hand side.
Therefore, y = kx
Given that y = 10 and x = 20
Substitute y and x in the equation above. We have;
10 = k(20)
10 = 20k
20k = 10
k = 10/20
k = 0.5
Since k = 0.5, the equation y = kx becomes y = 0.5x
Now, to find y if x = 15, substitute x in equation y = 0.5x
Therefore, y = 0.5(15)
y = 7.5
Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime =>
Prime Factorization of 4 is:
2 x 2 =>
Prime Factorization of 7 is:
7 is prime =>
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28