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Anvisha [2.4K]
4 years ago
8

1/2+3×2,by second power minus 1​

Mathematics
1 answer:
Katen [24]4 years ago
5 0

Answer:

11.5

Step-by-step explanation:

1/2=0.5

Follow PEMDAS

0.5+(3*(2^2))-1

2^2=4

4*3=12

12-1=11

11+0.5=11.5

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Sandra saves 10% of her salary for retirement. This year her salary was $1,000 more than in the previous
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Answer:

$41000

Step-by-step explanation:

If her salary was $1,000 more than the previous year and she save $4,200, $4,200 was 10% of her salary. So we should create an equation. (x being her salary from the previous year)

0.1(x+1000)=4200 (divide 4200 by .01)

x+100=42000

42000-1000= 41000

6 0
3 years ago
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The sum of two numbers is 39. The second number is 3 more than three times the first number. Let x represent the first number an
GenaCL600 [577]

Answer:

The\: value \:of\: the\: first\: number\:is\:9

Step-by-step explanation:

We\:have\:a\:system\:of\:equation:\\\left \{ {{x+y=39} \atop {3x+3=y}} \right. \\\Leftrightarrow \left \{ {{39-x=y} \atop {3x+3=39-x}} \right. \\\Leftrightarrow \left \{ {{39-x=y} \atop {4x=36}} \right. \\\Leftrightarrow \left \{ {{y=39-9} \atop {x=9}} \right. \\\Leftrightarrow \left \{ {{y=30} \atop {x=9}} \right. \\\Rightarrow x=9

6 0
3 years ago
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What is the volume of the triangular prism below
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The answer is 117. Ask him if he can help you with your work
6 0
4 years ago
Without these two things, a graph will not make sense.
Anna [14]
Are you going to tell me what you meant by that? when you messaged me?

3 0
3 years ago
In a trapezoid ABCD with legs AB and CD, the diagonals intersect each other at point O. Compare the areas of △ABO and △CDO.
atroni [7]

ar(ΔABO) = ar(ΔCDO)

Explanation:

The image attached below.

Given ABCD is a trapezoid with legs AB and CD.

AB and CD are non-parallel sides between the parallels AD and BC.

In ΔABD and ΔACD,

We know that, triangles lie between the same base and same parallels are equal in area.

⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.

Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)

Now consider ΔABO and ΔCDO,

Subtract ar(ΔAOD) on both sides of (1), we get

ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)

⇒ar(ΔABO) = ar(ΔCDO)

Hence, ar(ΔABO) = ar(ΔCDO).

4 0
3 years ago
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