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Vitek1552 [10]
3 years ago
9

At a local tech school, there are 6 math classes and each class has 27 students. The school pays for the book and calculators fo

r each student. Each book costs $45.10 and each student calculator costs $57.80. What’s is the total cost the school will pay ?
Mathematics
1 answer:
umka21 [38]3 years ago
6 0

The first step to solve this problem, you have to compute first for the total number of students:

6 math classes x 27 students per class = 162 students

Now, you know that there are 162 students all in all in the school. The next step is to compute for the total cost of both the book and the calculator per student.

$45.10 (Book) + $57.80 (Calculator) = $102.90 (total cost per student)

To compute for the total cost that the school will pay, you have to multiply the total cost per student to the number of students in school.

$102.90 per student x 162 students = $16,669.80

Therefore, the total cost the school will pay is $16,669.80.

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PART ;

......Circle A.................
Circumference - 2 pi r
25.12 = 2pi(4)
25.12 = 8i
Divide both sides by 8!!
3.14=pi

...Circle B.....................
Circumference = 2 pi r
9.42 = 2pi(3/2)
9.42 = 3pi
Divide both sides by 3!!!
3.14 = pi

PART B

.............Circle A...............
A=pi r ^2
50.24 = pi(4)^2
50.24=16pi
Divide both sides by 16!!!
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.............Circle B.............
A=pi r^2
7.065=pi(3/2)^2
7.065= 9pi/4
Divide both sides by 9/4!!!
3.14=pi

PART C

They used exactly 3.14 for the value of pi in CIRCLE A and B to get the circumference and the area :D

I hope this makes sense!!! 
When I wrote 'pi', it was supposed to be the symbol for pi. 
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For the equations given above, which statement is true?
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Thus, the 2 equations have the same solution.


We could have achieved this result also by noticing that the second equation is equivalent to first one, adding 6 to both sides.


Answer: A) The equations have the same solution because the second can be obtained by adding 6 to both sides of the first equation.
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