Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
Answer:
The value of x is 6 and -6. The smallest value of x is -6
Step-by-step explanation:
2/3 x² = 24
solving this equation for finding the value of x.
Multiply both sides by 3/2
x² = 24 * 3/2
x² = 72/2
x² = 36
Now, to find the value of x taking square root on both sides
√x² = √36
x= ±6
So, the value of x is 6 and -6. The smallest value of x is -6
Answer: (4,4)
Step-by-step explanation:
(1,-4) reflected over the x-axis is (1,4). Then translated 3 units up is (4,4). Hope this helps
