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3 years ago

PLEASE HELP RIGHT AWAY

Mathematics

1 answer:

Rainbow [258]3 years ago

7 0

Answer:

Approximately 53

Step-by-step explanation:

This is a geometric progression, because each term is found by multiplying the previous one by a constant factor.

In our case, the first term is know (a1 = 3), and the growth factor is also known (q = 1.333333).

What we are tasked to do is to find the 11th (n=11) term of the series, since it asks for AFTER the 10th roll.. That's easy with the base formula:

$a_{n} = a_{1} q^{n-1}$

Let's place the values we have in the equation and solve it:

$a_{10} = 3 * (1.333333)^{11-1} = 3 * (17.758) = 53.3$

So, after the 10th roll, you should need 53 dice, approximately.

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In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem

Damm [24]

Answer:

a) P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) = 0,7120 or 71,2 %

c) P(C) = 0,2055 or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )! ⇒ C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2 ⇒ C ( 24,4) = 10626

TE = 10626

Splitting the group of tanks in two 6 with h-v and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3) = 6 * 18! / 3!*15! = 18*17*16*15!/15!

FE = 4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2 = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120 or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2 ⇒ FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055 or P(C) = 20,55 %

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3 years ago

There is a discount of sale of 20% off of a $450 pair of skis how much is the discount ?

g100num [7]

Answer:

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Step-by-step explanation:

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2 years ago

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What is m<br> A.55°<br> B.58°<br> C.122°<br> D.125°

Andreyy89

Answer: k = 55 degrees

Step-by-step explanation:

to find J, subtract 122 from 180, you get 58. The total number of degrees is 180. Since L is given as 67, and 67+58=125. Simply subtract 125 from 180 which is 55 degrees

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3 years ago

#10 AH IM STUCK ON THIS ITS HARD HELP

Dafna11 [192]

Answer:

4.8 in

Step-by-step explanation:

feet to inch conversion is *12

2 * 12 = 24

then divide the scale (for every 1 in on the model there is 5 in on the actual, so divide the actual value by 5)

24/5 = 4.8

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1 year ago

On a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system.

Mashutka [201]

we have

$y\leq \frac{1}{4}x+3$ ----> inequality 1

The solution of the inequality 1 is the shaded area below the solid red line

The solution is the region D and region C

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The solution of the inequality 2 is the shaded area above the solid blue line

The solution is the region B and region C

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The solution is the region C

see the attached figure

therefore

the answer is the option C

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