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babymother [125]
3 years ago
7

PLEASE HELP RIGHT AWAY

Mathematics
1 answer:
Rainbow [258]3 years ago
7 0

Answer:

Approximately 53

Step-by-step explanation:

This is a geometric progression, because each term is found by multiplying the previous one by a constant factor.

In our case, the first term is know (a1 = 3), and the growth factor is also known (q = 1.333333).

What we are tasked to do is to find the 11th (n=11) term of the series, since it asks for AFTER the 10th roll..  That's easy with the base formula:

a_{n} = a_{1} q^{n-1}

Let's place the values we have in the equation and solve it:

a_{10} = 3 * (1.333333)^{11-1} = 3 * (17.758) = 53.3

So, after the 10th roll, you should need 53 dice, approximately.

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