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alina1380 [7]
3 years ago
12

What runners are in a proportional relationship with each other

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Velocity=distance/time

Liam: 0,5 / 306,6  ≅ 0,0016307893020221787345075016307 miles/s

Taylor: 1,2 / 756,36  ≅ 0,001586546089163890211010629858 miles/s

Sarah: 0,7 / 504,35  ≅ 0,0013879250520471894517696044413 miles/s

Ashley: 0,75 / 459,9  ≅ 0,0016307893020221787345075016307 miles/s

Connor: 1 / 600,5  ≅ 0,0016652789342214820982514571190 miles/s

Nathan: 1,5 / 942,75  ≅ 0,0015910898965791567223548130469 miles/s

Juan: 1,35 / 827,82  ≅ 0,0016307893020221787345075016307 miles/s

Katie: 0,6 / 429,48  ≅ 0,0013970382788488404582285554624 miles/s

Liam, Ashley, Juan have the same velocity.

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

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2 years ago
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Answer:

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Step-by-step explanation:

Thale’s Theorem

5x-8=90

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The percentage increased by approximately 5%.

Step-by-step explanation:

52.10 - 49.62 = 2.48

2.48/49.62 x 100 = 4.998%

The percentage increase in the price is approximately 5%. Hope this helps! :)

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