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alina1380 [7]
3 years ago
12

What runners are in a proportional relationship with each other

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Velocity=distance/time

Liam: 0,5 / 306,6  ≅ 0,0016307893020221787345075016307 miles/s

Taylor: 1,2 / 756,36  ≅ 0,001586546089163890211010629858 miles/s

Sarah: 0,7 / 504,35  ≅ 0,0013879250520471894517696044413 miles/s

Ashley: 0,75 / 459,9  ≅ 0,0016307893020221787345075016307 miles/s

Connor: 1 / 600,5  ≅ 0,0016652789342214820982514571190 miles/s

Nathan: 1,5 / 942,75  ≅ 0,0015910898965791567223548130469 miles/s

Juan: 1,35 / 827,82  ≅ 0,0016307893020221787345075016307 miles/s

Katie: 0,6 / 429,48  ≅ 0,0013970382788488404582285554624 miles/s

Liam, Ashley, Juan have the same velocity.

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Your paint 1/3 of a wall in 1/4 hour. at this rate, how long will it take to paint one wall
Irina-Kira [14]

1/4 hour is the same as 15 minutes. If it takes 15 minutes to paint 1/3, then it would take 45 minutes to paint the whole wall.

8 0
3 years ago
Please help ASAP I CAN FIGURE IT OUT
OleMash [197]

The last option is the answer

X =3

8 0
2 years ago
The figure shown is created by joining three rectangles. Enter the area of the figure, in square centimeters. Round to the neare
Basile [38]

Answer:

235

Step-by-step explanation:

first, separate the floor into 3 different rectangles to calculate the area and then add them together.

area of rec=L*B

rec 1: 9*12.5=112.5

rec 2: (13.5-5.5)*(19.5-9-7)=28

rec 3:7*13.5=94.5

Then:

112.5+28+94.5=235

7 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
If f(x) = x^2 - 3x + 1 over 2, determine f ( 4 ) .
svet-max [94.6K]
F(x)=x^2-3x+1/2, if f(4)
Substitute x with 4, to get
f(x)=x^2-3x+1/2
f(4)=4^2-3(4)+1/2
f(4)=16-12+1/2
f(4)=4+1/2
f(4)=4 1/2 or 4.5. Hope it help!
7 0
3 years ago
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