Question

Please simplify the answer

Answer 1

Answer:

$56\: in^2$

Step-by-step explanation:

• Surface area of the net = 4* Area of one triangle + Area of square

• $= 4*\frac{1}{2}*4*5 + (4)^2$

• $= 40 + 16$

• $= 56\: in^2$