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ryzh [129]
3 years ago
7

Which phrase describes the role of the mitochondria?

Biology
1 answer:
slega [8]3 years ago
8 0
The role of mitochondria is to supply energy to the cells

Which is which is why the answer is A. The powerhouse of the cell


Mithochondria can transfrom oxygen to generate energy for the cell. For example, brain cells in our brain need a lot of  energy to process all the information what we inputted, thats when mitochondria took part.
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In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0
3 years ago
The recycling of which compound ensures the continuation of glycosys under anaerobic conditions
gizmo_the_mogwai [7]
I think the answer is C. NAD+
6 0
3 years ago
A bird flies at 12.5 meters per second. the wind speed is 4.5 meters per second. what is the speed of the bird when it flies wit
Agata [3.3K]

Answer:

17m/s

Explanation:

Given parameters:

Speed of the bird  = 12.5m/s

Speed of the wind  = 4.5m/s

Unknown:

Speed of the bird when it flies with the wind = ?

Solution:

The speed of the bird when it flies with the wind is the sum of the speed of the bird and the speed of the wind.

  Speed of the bird with wind  = 12.5m/s + 4.5m/s  = 17m/s

3 0
3 years ago
an blank pool contains all the alleles different members of a population have and can pass on to their offspring
kykrilka [37]
They can make more offspring
6 0
3 years ago
A young child has a middle ear infection: otitis media. There is a build-up of fluid, bacteria, and white blood cells, or pus, i
IceJOKER [234]
The build up in the child's ear prevent sound from reaching the eardrum.
7 0
2 years ago
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