I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer: the answer should be 7
Step-by-step explanation: V=πr2h
3=π·1.52·3
3≈7.06858
you can find the radius for the area of the base 7 by dividing by like such 7/3.1459 the squared because remember its in r2 form which give you 1.5 then plug this in for one of two ways to solve A· 1/3 or V=πr2h
1. 150* .40 = 60 so 150 -60 = 90 so the markdown price is $90
2. 18.99*.25 =4.75 (rounded ) so 18.99-4.75 is $14.24 as your markdown price
3. 95 * .10= 9.5 so 95- 9.5 = $85.50 as your markdown price
4. 75*.15=11.25 so 75-11.25=$63.75 as your markdown price
Answer: 8 First class tickets
Step-by-step explanation:
You can set up a system of equations for this problem. Let x = number of coach tickets and y = number of first class tickets. Then:
330x + 1220y = 12730 (cost of coach tickets plus cost of first class tickets is total budget)
x + y = 17 (number of coach tickets plus number of first class tickets is total number of people)
Solve the second equation for y to get y = 17 - x, then plug that into the first equation and solve for x:
330x + 1220(17 - x) = 12730
330x + 20740 - 1220x = 12730
-890x + 20740 = 12730
-890x = -8010
x = 9
Sarah bought x = 9 coach tickets. Plug that into the second equation and solve for y:
9 + y = 17
y = 8
Sarah bought y = 8 first class tickets.