You need to find the area of the hexagon, and the area of the triangle.
The formula for the area of a triangle is
I hope this helps you a little.
this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?
Answer:
Reasons:
The given parameters are;
Distance between the two stations = 146 miles
Location of the weather balloon from the Western station = N35°E
Location of the weather balloon from the Eastern station = N23°E
The location of the station = On the equator
Required:
The distance of the balloon from the Western station
Solution:
- The angle formed between the horizontal, and the line from the Western station
to the balloon = 90° - 35° = 55°
- The angle formed between the horizontal, and the line from the Eastern station
to the balloon = 90° + 23° = 113°
The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°
By sine rule,
Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)
Therefore;
Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4
Step-by-step explanation:
Answer:
mee too
Step-by-step explanation:
Answer:
We have the function g(x) = x^3 -15*x
First, to find extrema, we can find the zeros of the first derivative.
g'(x) = 3*x^2 -15
g'(x) = 0 = 3*x^2 - 15
x^2 = 15/3 = 5
x = √5
x = -√5
Now, watching at the second derivative we have:
g''(x) = 6*x
so when we have
g''(√5) = 6*√5 > 0 then x = √5 is a local minimum
g''(-√5) = -6*√5 < 0, then x = -√5 is a local maximum.
