What are the coordinates of the focus and the equation of the directrix?
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Answer:
Hey there!
First, we want to find the side length of the large triangle.
1/2bh=y cm^2
bh=2y cm^2
Since b and h are the same here, we have b^2= 2y, .
And we have FC=.
Area of shaded triangle: .
This is equal to: , or y/4.
Let me know if this helps :)