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sveticcg [70]
1 year ago
7

HELP DUE TOMORROW GUYS

Mathematics
1 answer:
kakasveta [241]1 year ago
6 0

Answer:

x = 15

Step-by-step explanation:

8x + 9 and 51 are same- side interior angles and sum to 180° , then

8x + 9 + 51 = 180

8x + 60 = 180 ( subtract 60 from both sides )

8x = 120 ( divide both sides by 8 )

x = 15

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5 divided by 5.2 = ?
Alenkasestr [34]

Answer:

0.96153846153

but it would make more sense in a lot of cases if it was 5.2/5

Step-by-step:

5 0
3 years ago
Read 2 more answers
A Ladder That Is 5 meters in length is resting on a branch of a tree and the base of the ladder is 3 meters from the tree on the
Stells [14]
Use  the Pythagoras theorem:-

height = sqrt(5^2 - 3^2 ) =  sqrt16  = 4 metres  Answer.



5 0
3 years ago
3y - 5x = 9<br> Y= -5/3x-12<br> Are the parallel
bija089 [108]

Answer:

Both lines are not parallel

Step-by-step explanation:

Given as :

Two lines equation are as :

3y - 5x = 9   And  y = - \frac{5}{3}x - 12

First line is now written in eq y = mx + c

Or,    3y = 5x + 9

Or,      y = \frac{5}{3}x +  \frac{9}{3}

So, Slop of this line ( m 1 ) =  \frac{5}{3}

     slop of second line ( m 2) is  \frac{- 5}{3}

∵ The slop of both lines are not equal , so the line are not parallel to each other .

Hence Both lines are not parallel     Answer  

6 0
3 years ago
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? {5, 8} {-5, -8} {3, 8} {4, 7} {4, 8}
Sergeu [11.5K]
I think the answer is {5,8}
4 0
3 years ago
A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each d
yuradex [85]

Answer:

a) lower limit = 4.295 minutes

b) upper limit = 6.365 minutes

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 5.33 minutes

Standard deviation r = 1.33 minutes

Number of samples n = 11

Confidence interval = 99%

z(at 99% confidence) = 2.58

Substituting the values we have;

5.33+/-2.58(1.33/√11)

5.33+/-2.58(0.401010088288)

5.33+/-1.0346060277

5.33+/-1.035

= ( 4.295, 6.365) minutes

Therefore at 99% confidence interval (lower, upper limit) = ( 4.295, 6.365) minutes

a) lower limit = 4.295 minutes

b) upper limit = 6.365 minutes

3 0
3 years ago
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