Answer:
0.14secs
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t)=-4.9t^2-v_0 t+h_0
Given v0 = 12m/s
h0 = 1.8m
The equation becomes
h(t)=-4.9t^2-12t+1.8
The height of the ball on the ground level is zero
Substituting into the equation
0 = -4.9t^2-12t+1.8
Multiply through by -10
49t²+120t-18 = 0
Factorize and get t:
t = -120±√120²-4(49)(-18)/2(49)
t = -120±√14400+ 3528/98
t = -120±√17928/98
t = -120±133.89/98
t = 13.89/98
t = 0.14secs
Hence it takes 0.14secs until it reaches the ground
Answer:
On a coordinate plane, a line goes through (0, 3) and (3, negative 1).
Answer:
Range is given by the second option: {}.
Step-by-step explanation:
Range is the set of possible values in a given function.
Here, the function is defined by the following ordered pairs:
The y values of the function are {}
Therefore, the range is given as {}.
So, the second option is correct.
Answer:
<em>3.94 seconds </em>
Step-by-step explanation:
h = - 16t² + 248
If stone is dropped, then h = 0
- 16t² + 248 = 0
t² =
t = ±
t < 0 is a solution of equation, but not a solution of the task
t = ≈ <em>3.94 seconds</em>