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NeX [460]
4 years ago
6

Glycolysis is the first stage of cellular respiration producing atp.what is the net gain of atp molecules per molecule of glucos

e from glycolysis
Biology
1 answer:
suter [353]4 years ago
7 0

The net gain of ATP molecules per molecule of glucose in the reactions of glycolysis is 2.

Glucose is the main source of almost all energy used by cells of similar and different organisms.

In glycolysis process, the production of two pyruvate molecules, a net gain of two ATP molecules, and two NADH molecules takes place.

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Mosses form spores in capsules

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In the cranes what does songsam recall in the two flashbacks to his childhood? explain how these memories motivate songsam's act
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The "Cranes" is a short story book written by Hwang Sunwon. The story is set in Korea during the Korean War and focuses on two childhood friends, Songsam and Tokchae, who are on opposite sides during the war. Songsam has two flashbacks of his childhood memories with his friend Tokchae, where he remembers how they used to climb the trees and catch cranes. These flashbacks act as a reminder of the times he had spent with his friend and the importance of this friendship. As a result, these memories motivate him to let Tokchae free.
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Define mutation and mutagen.
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Suppose you found a fossil of a clam shell what can you conclude about the once-living organism and how it became a fossil?
Stolb23 [73]

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Identifying the fossil is the first step. We have already identified this fossil as a clamshell. We know clam are from the sea, but if you didn't, you could conclude this from knowing where you found the fossil (likely near the beach). Discovering where it is can also lead you to a conclusion on it's arrival as a fossil, perhaps washed up on shore or buried by an animal.

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Explain how we know that DNA breaks and rejoins during recombination.
alisha [4.7K]

Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

           Previously we defined its general characteristics. We will now describe a molecular model of this recombination, based on the classic Meselson and Radding, modified with the latest advances. Do not forget that we are facing a model, that is, a hypothetical proposal to explain a set of experimental data. Not all points of this model are fully clarified or demonstrated:

           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

1) Start of recombination: Homologous recombination begins with an endonucleotide incision in one of the donor double helix chains. Responsible for this process is the nuclease RecBCD (= nuclease V), which acts as follows: it is randomly attached to the donor's DNA, and moves along the double helix until it finds a characteristic sequence called c

Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

3) The displaced single chain zone of the donor DNA is coated by subunits of the RecA protein (at the rate of one RecA monomer per 5-10 bases). Thus, that simple chain adopts an extended helical configuration.

4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

5) It is assumed that the newly displaced chain of the recipient DNA (D-structure) is digested by nucleases.

6) Covalent union of the ends originating in the two homologous chains. This results in a simple cross-linking whereby the two double helices are "tied." The resulting global structure is called the Holliday structure or joint.

7) Migration of the branches: a complex formed by the RuvA and RuvB proteins is attached to the crossing point of the Holliday structure, which with ATP hydrolysis achieve the displacement of the Hollyday crossing point: in this way the portion of heteroduplex in both double helices.

8) Isomerization: to easily visualize it, imagine that we rotate the two segments of one of the DNA c.d. 180o with respect to the cross-linking point, to generate a flat structure that is isomeric from the previous one ("X structure").

9) Resolution of this structure: this step is catalyzed by the RuvC protein, which cuts and splices two of the chains cross-linked at the Hollyday junction. The result of the resolution may vary depending on whether the chains that were not previously involved in the cross-linking are cut and spliced, or that they are again involved in this second cutting and sealing operation:

a) If the cuts and splices affect the DNA chains that were not previously involved in the cross-linking, the result will be two reciprocal recombinant molecules, where each of the 4 chains are recombinant (there has been an exchange of markers between donor and recipient)

b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

8 0
4 years ago
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