Answer: 
Step-by-step explanation:
Given
Length of the pipe 
Inside diameter of the pipe 
Outside diameter of the pipe 
Volume of the pipe
![\Rightarrow V=\dfrac{\pi }{4}[d_o^2-d_i^2]\\\\\text{Insert the values}\\\\\Rightarrow V=\dfrac{\pi}{4}[5^2-4^2]\times 10^{-4}\times 4\\\\\Rightarrow V=28.278\times 10^{-4}\ m^3\\\\\Rightarrow V=0.0028278\ m^3](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D%5Cdfrac%7B%5Cpi%20%7D%7B4%7D%5Bd_o%5E2-d_i%5E2%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B%5Cpi%7D%7B4%7D%5B5%5E2-4%5E2%5D%5Ctimes%2010%5E%7B-4%7D%5Ctimes%204%5C%5C%5C%5C%5CRightarrow%20V%3D28.278%5Ctimes%2010%5E%7B-4%7D%5C%20m%5E3%5C%5C%5C%5C%5CRightarrow%20V%3D0.0028278%5C%20m%5E3)
Answer:
both watered on the same day, If we multiply 18 by any number such as 2,3,4,5 we can find the next soonest date that they will both be watered on. 18*2,3,4,5 30,2,3,4,5
18*2,3,4 are not multiples of 30, 18*5 is 90
30*2 is not a multiple of 18, 30*3 is 90
Now we know the next closest date they will be watered again is 90 days from now.
Step-by-step explanation:
The slope of the line is 7 because it is a slope
The height of tree is 8 feet
<h3><u>Solution:</u></h3>
Given, Micah places a mirror on the ground 24 feet from the base of a tree
At that point, Micah's eyes are 6 feet above the ground
And he is 9 feet from the image in the mirror.
To find : height of tree = ?
Let "n" be the height of tree
From the question, we can see there is a directly proportional relationship between heights and distances.
Proportional relationships are relationships between two variables where their ratios are equivalent.
Hence, the height of the tree is 8 feet
and 
. The squared distance between any point in this region 
and the point (1, 1) is
![=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B%5Cdisplaystyle%5Cint_%7B%5Ctheta%3D0%7D%5E%7B%5Ctheta%3D2%5Cpi%7D%5Cint_%7Br%3D0%7D%5E%7Br%3D1%7D%5Br%5E2-2r%28%5Ccos%5Ctheta-%5Csin%5Ctheta%29%2B2%5Dr%5C%2C%5Cmathrm%20dr%5C%2C%5Cmathrm%20d%5Ctheta%7D%7B%5Cdisplaystyle%5Cint_%7B%5Ctheta%3D0%7D%5E%7B%5Ctheta%3D2%5Cpi%7D%5Cint_%7Br%3D0%7D%5E%7Br%3D1%7Dr%5C%2C%5Cmathrm%20dr%5C%2C%5Cmathrm%20d%5Ctheta%7D)
