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3 years ago

6

The factorization of x^2 + 3x-4 is modeled with algebra tiles

1 answer:

o-na [289]3 years ago

5 0

Answer:

(x-1) (x+4)

Step-by-step explanation:

i used something called the box method, basically the way i got the answer is what equals 3 when added, but multiplies to make -4

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bixtya [17]

Answer:

Triangle 1 has the most area

Step-by-step explanation:

Because triangle has more whole blocks and also sides

hope this helps. if it's wrong im sorry :(

7 0

3 years ago

Help geometry what I m jlf <br> Picture provided

Zolol [24]

Answer:

$\angle\,JLF = 114^o$ which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from $180^o$ , since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as $90^o$ and $138^o$ . (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : $360^o-90^o-138^o=132^o$

Therefore, the two equal acute angles in the triangle JOH should add to:

$180^o-132^o=48^o$ resulting then in each small acute angle of measure $24^o$ .

Now referring to the green sided right angle triangle we can find find angle JLG, using: $180^o-24^o-90^o=66^o$

Finally, the requested measure of angle JLF is obtained via: $180^o-66^o=114^o$

4 0

3 years ago

Please help me with thissss

Evgesh-ka [11]

Answer:

a.) The sum of the weights of the two in insects is 0.0031 grams. (0.0031 grams)

b.) The fly is 0.0013 grams heavier than the gnat. (0.0013 grams)

Step-by-step explanation:

2.2 * 10^-3 = 2.2 * 1/1000 which is 2.2/1000.

9 * 10^-4 = 9 * 1/10000 = 9/10000

To add 9/10000 to 2.2/1000 we have to find the common denominator, which will be 10000.

So we do:

2.2/1000 * 10/10 = 22/10000

9/10000 + 22/10000 = 31/10000 = 0.0031.

The sum of the weights of the two in insects is 0.0031 grams.

To find how much heavier the fly is than the gnat we do:

22/10000 - 9/10000 = 13/10000 = 0.0013

The fly is 0.0013 grams heavier than the gnat.

7 0

3 years ago

Question<br><br> In the number 8.025, what number is in the tenths place?

sweet-ann [11.9K]

Answer:

the 0

Step-by-step explanation:

the 0 is in the tenths place

7 0

3 years ago

Read 2 more answers

What is the following sum? 2 (RootIndex 3 StartRoot 16 x cubed y EndRoot) 4 (RootIndex 3 StartRoot 54 x Superscript 6 Baseline y

san4es73 [151]

Equivalent expressions are expressions that have the same value, and can be used interchangeably.

The result of the sum $2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$ is $4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})$

The expression is given as:

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$

Rewrite the expression as:

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (\sqrt[3]{2^4x^3y}) + 4 (\sqrt[3]{3^3 \times 2x^6y^5})$

Evaluate the roots

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 2 (2x\sqrt[3]{2y}) + 4 (3x^2y\sqrt[3]{2y^2})$

Open the brackets

$2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5}) = 4x\sqrt[3]{2y} + 12x^2y\sqrt[3]{2y^2})$

The above expression cannot be further simplified.

Hence, the result of the sum $2 (\sqrt[3]{16x^3y}) + 4 (\sqrt[3]{54x^6y^5})$ is $4x\sqrt[3]{2y} + 8x^2y\sqrt[3]{2y^2})$

Read more about equivalent expressions at:

brainly.com/question/2972832

7 0

3 years ago

Read 2 more answers