Answer:
Mean =
Standard deviation =
Step-by-step explanation:
x P(x)

33 0.02 0.66 21.78
34 0.06 2.04 69.36
35 0.1 3.5 122.5
36 0.2 7.2 259.2
37 0.24 8.88 328.56
38 0.26 9.88 375.44
39 0.1 3.9 152.1
40 0.02 0.8 32
1 36.86 1360.9
We are supposed to find mean and standard deviation
Mean =
Standard deviation =
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.
Given that </span><span>DG = 5 cm and BD = 12 cm, then

Since AG = BG = CG, therefore, CG = 13 cm.</span>
Answer:
-38
Step-by-step explanation:
Answer:
739
Step-by-step explanation:
a sub 92 = 11 + (92 - 1) * 8
a sub 92 = 11 + 728
a sub 92 = 739
Answer:
multiply 3x-2(x+8)
Step-by-step explanation:
PEMDAS
also you must simplify both sides to solve this problem and that's the first step to simplifying this side (the other one is simplified)