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Mashutka [201]
3 years ago
8

Find the least common denominator for these two rational expressions. x²/x²+2x+1 and 5/x²+4x+3

Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0
Factor each denominator:

x^2 + 2x + 1 = (x+1)^2

x^2 + 4x + 3 = (x+3)(x+1)

Now take the common and non common factors with the highest exponents and multiply them.

(x+3).(x+1)^2 is the least common denominator.

If you expand that product you will get x^3 + 5x^2 + 7x +3
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Answer:

y=1/3x-1/3

Step-by-step explanation:

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When reviewing all the answers per pound for feed, chicken feed is the most expensive per pound.

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3 years ago
Joshua places the letters in the word SNOWMAN in a bag. A letter is drawn randomly and not replaced. Then another letter is sele
oksano4ka [1.4K]

Answer:

13/42

Step-by-step explanation:

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7 0
2 years ago
A landlord owns 3 condominiums, a 1-bedroom condo, a 2-bedroom condo, and a 3-
marusya05 [52]

Answer:

I bedroom condo = $280

2 bedroom condo = $400

3 bedroom condo = $560

Step-by-step explanation:

Given that :

Total rental cost for all 3 condos = $1240

Let :

I bedroom condo = b

2 bedroom condo = c

3 bedroom condo = 2b

Hence,

b + c + 2b = 1240

3b + c = 1240 - - - (1)

REPAIR COST :

Total repair cost = $276

1 bedroom = 10% of b = 0.1b

2 bedroom = 20% of c = 0.2c

3 bedroom = 30% of 2b = 0.3 * 2b = 0.6b

Hence,

0.1b + 0.2c + 0.6b = 276

0.7b + 0.2c = 276 - - - (2)

From (2)

0.7b + 0.2c = 276

0.7b = 276 - 0.2c

b = (276 - 0.2c) / 0.7

Substitute b = (276 - 0.2c) / 0.7 into (1)

3(276/0.7 - 0.2c/0.7) + c = 1240

1182.8571 - 0.8571428c + c = 1240

1182.8571 + 0.1428571c = 1240

0.1428571c = 1240 - 1182.8571

0.1428571c = 57.1429

c = 57.1429 / 0.1428571

c = 400

3b + c = 1240

3b + 400 = 1240

3b = 1240 - 400

3b = 840

b = 840/3

b = 280

Hence,

I bedroom condo = $280

2 bedroom condo = $400

3 bedroom condo = 2(280) = $560

6 0
2 years ago
In throwing a die what is the probability of getting even or prime number​
Julli [10]

die number : 1 2 3 4 5 6

<em>p</em><em>r</em><em>o</em><em>b</em><em>a</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>o</em><em>f</em><em> </em><em>g</em><em>e</em><em>t</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>e</em><em>v</em><em>e</em><em>n</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>:</em><em> </em><em>3</em><em>/</em><em>6</em>

because the number 2,4,6 are even number

the number 3 is 'how many even number?'

while 6 is the total number in throwing a die

<em>p</em><em>r</em><em>o</em><em>b</em><em>a</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>o</em><em>f</em><em> </em><em>g</em><em>e</em><em>t</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>p</em><em>r</em><em>i</em><em>m</em><em>e</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em> </em><em>:</em><em> </em><em>2</em><em>/</em><em>6</em>

because the number 3,5 are only prime number

the number 2 is 'how many prime number?'

while 6 is the total number in throwing a die

the question ask : getting even OR prime number

this means that we have to add the probability of even and prime number

3/6 + 2/6 = 5/6 (answer)

5 0
3 years ago
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