Find the least common denominator for these two rational expressions. x²/x²+2x+1 and 5/x²+4x+3

1 answer:

5 0

Factor each denominator:

x^2 + 2x + 1 = (x+1)^2

x^2 + 4x + 3 = (x+3)(x+1)

Now take the common and non common factors with the highest exponents and multiply them.

(x+3).(x+1)^2 is the least common denominator.

If you expand that product you will get x^3 + 5x^2 + 7x +3

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Explain how the common difference in an arithmetic sequence is like the slope of a linear function. read more >>

faust18 [17]

In arithmetic sequence, let the first tern of the arithmetic sequence be, a, and the common difference, d, then the nth term, Tn, of the arithmetic sequence is given by:

$T_n=a+(n-1)d$

For a linear function with y-intercept, c, and slope, m, the linear function is given by:

$y=mx+c$

Comparing the equation of the arithmetic sequence and that of the linear function, we can see that y is compared to Tn, a is compared to c, m is compared to d, and x is compared to n - 1.

Therefore, <span>the common difference in an arithmetic sequence is like the slope of a linear function as both are multiple of a variable.</span>

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Answer:

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Step-by-step explanation:

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Read 2 more answers

Question 3

Fiesta28 [93]

Answer: y = -6x + 2

m = y_2 - y_1
/ x_2 - x_1

-10 - 8
/ 2 - (-1)

= -18/3 = -6

m (slope) = -6

y = mx + b
y = -6x +b

Find b using (-1,8)
y = -6x +b
8 = -6(-1) + b
8 = 6 + b
-6 -6
2 = b

Final answer: y = -6x + 2

To check using one of the points: (-1,8) or (2,-10)
y = -6x + 2
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-10 = -12 + 2
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Step-by-step explanation:

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