Hey there!
2^4=2x2x2x2
2*2=4
4*2=8
8*2=65
It equals 64.
Hope this helps! Let me know if you have any questions:)
Answer:
yea
Step-by-step explanation:
Answer:
Volume ≈ 33.33 cubic feet
Step-by-step explanation:
The question is:
<em>Find the volume of a right square pyramid with base square edges measuring 5 feet each and a height of the pyramid be 4 feet.</em>
<em />
So, the base is a square with side length 5 feet.
And the height of the pyramid is 4 feet.
The volume of a pyramid is given by the formula:
![V=\frac{a^2 h}{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Ba%5E2%20h%7D%7B3%7D)
Where
a is the square base side length (given as 5)
h is the height of the pyramid (given as 4)
Now we substitute and find the value:
![V=\frac{a^2 h}{3}\\V=\frac{(5)^2 (4)}{3}\\V=33.33](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Ba%5E2%20h%7D%7B3%7D%5C%5CV%3D%5Cfrac%7B%285%29%5E2%20%284%29%7D%7B3%7D%5C%5CV%3D33.33)
The volume is around 33.33 cubic feet
Answer: 38 feet.
Step-by-step explanation:
The equation of motion of a body thrown vertically upwards:
,
![h_0=2 \ feet\ \ \ \ v_0=50\ feet\ per\ second.](https://tex.z-dn.net/?f=h_0%3D2%20%5C%20feet%5C%20%5C%20%5C%20%5C%20%20v_0%3D50%5C%20%20feet%5C%20%20per%5C%20%20second.)
Substitute in formula (1) the value t=2 c:
![h=2+50*2-16*2^2\\h=2+100-16*2*2\\h=102-64\\h=38\ feet.](https://tex.z-dn.net/?f=h%3D2%2B50%2A2-16%2A2%5E2%5C%5Ch%3D2%2B100-16%2A2%2A2%5C%5Ch%3D102-64%5C%5Ch%3D38%5C%20feet.)