Ask question

Ask question

All categories

3 years ago

7

vector has 4 orange picks for every 3 green picks. if 8 of the picks are orange, how many picks are green?

2 answers:

Lesechka [4]3 years ago

7 0

6 picks are green (see pic)

lisabon 2012 [21]3 years ago

3 0

.................... aaaaaaaaaaa bbbbbbvvb

You might be interested in

dolphi86 [110]

Answer:

Find the unit rate of each printing machine and compare.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Stephanie has a photo album with 500 pages each photo takes up 1/3 of a page how many photos can she put in the album

laila [671]

166 2/3 hope this helps

7 0

3 years ago

Read 2 more answers

beth wants to make bags of party favors to give to her friends. Bracelets come in package of 10. Hair bows come in package of 4.

Paladinen [302]

10 = 2x5

4 = 2x2

LCM + 2x2x5 = 20 <=== smallest number of bracelets and hair bow to buy

6 0

3 years ago

if rounded to the nearest dime what is the greatest amount of money that rounds to $105.40? what is the least amount of money th

Kamila [148]

The greatest amount of money would be $105.40. The least amount would also be $105.40. Because the zero is less than five the dollar amount would stay the same.

4 0

3 years ago

Read 2 more answers

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago