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motikmotik
3 years ago
6

Help on this question ​

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

sec t = 1/(cos t) = 1/(-3/4) = -4/3

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Need help, please answer correctly for branliest!
Dmitry_Shevchenko [17]

Answer:

68 degrees

Step-by-step explanation:

90 - 22 = 68 degrees

when you see the square looking thing it indicated a right angle which is equal to 90 degrees :)

4 0
3 years ago
Read 2 more answers
Need help asap this is due in 20 min!!! i will gove brainliest too! questions 8-11
andreev551 [17]

8. x= 7

9. x= 9

10. x= -10

11. x= -18

7 0
3 years ago
Round 29,857 to the nearest ten thousand
lesya692 [45]
The answer is 30,000 because the nine makes you round the thousands higher and makeing the rest 0.
4 0
3 years ago
Read 2 more answers
2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.
vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

a_1 = 2.8

a_2 = 3.4

Common difference = a_2 - a_1 = 3.4 - 2.8 = 0.6.

Expression for the nth term:

a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n

n = 50 for the fiftieth term. Therefore

a_{50} = 2.2 + 0.6 \times 50 = 32.2.

6 0
3 years ago
True or false 6,859^1/3 can be written as square root 3 19^3
Dennis_Churaev [7]
6859^{ \frac{1}{3}}

Using the index law a^{ \frac{m}{n}} =  (\sqrt[n]{a} )^m

\sqrt[3]{6859}=19, so we can also write this as
( \sqrt[3]{19^3} )

Answer: TRUE

7 0
3 years ago
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