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STatiana [176]
3 years ago
12

the shedd family had an 8' by 6' rectangular patio built for a cost of $1134. What is the number of dollars in the cost per squa

re foot?
Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0
You can do 8*6 to find the area to be 48 ft. squared. So then we can do:
$1134/48 ft. to find the price per foot to be $23.63, or $24 rounded up

Hope this helps 
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What is the estimate of 234,444,043
Nataly_w [17]

Answer:

200,000,000

or 230,000,000  depending on what place your rounding to

Step-by-step explanation:

4 0
3 years ago
I need help on #16 and #14, when I did question 15 it was fine but I keep running into problems on how to solve 14 and 16
Inessa [10]
The area of a circle is pi*r^2.
The angles in a circle add up to 360 degrees.

Let's say I have a circle with radius 2.
The total area of the circle is pi* (2^2) = 4pi

Let's say I cut out 15 degrees of this circle. This piece is 15 out of 360 of the whole circle.

The area of this part is (15/360) * 4pi

The rest of the area is (360-15)/360 * 4pi.

I hope this helps.
4 0
4 years ago
Read 2 more answers
13. A local car wash is open 8 hours each day.
Mila [183]
68 containers because 8.5 * 8 is 68
5 0
3 years ago
Remove parentheses by applying the Distrubitive Property. 5x^2(7- x^2)
Sunny_sXe [5.5K]

Answer:

35x^2-5x^4

Step-by-step explanation:

You have to multiply the numbers on the outside to the numbers on the inside.

For example, 5x^2 times 7 would be 35x^2.

3 0
3 years ago
One positive integer is 3 greater than 4 times another positive integer. If the product of the two integers is 76, then what is
andrew11 [14]

Answer:

The sum of the two integers is 23

Step-by-step explanation:

Let one integer be x and the other integer be y

Then according to the statement "One positive integer is 3 greater than 4 times another positive integer.."

x be the integer that is One positive integer is 3 greater than 4 times another positive integer.

Then

x= 3+4y----------------------------------(1)

Product of the two integer is 76, this can  written as

x \times y =76

substituting the values of x from eq(1)

( 3+4y) \times y =76

3y + 4y^2 = 76

3y + 4y^2-76= 0

4y^2 + 3y -76= 0

Solving the quadratic equation equation we get

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

here

a = 4

b= 3

c = -76

susbtituting the above values in the formula

y=\frac{-3 \pm \sqrt{3^2-4(4)(-76)}}{2(4)}

y=\frac{-3 \pm \sqrt{9- 4(4)(-76)}}{8}

y=\frac{-3 \pm \sqrt{9- (16)(-76)}}{8}

y=\frac{-3 \pm \sqrt{9- (-1216)}}{8}

y=\frac{-3 \pm \sqrt{9 + 1216}}{8}

y=\frac{-3 \pm \sqrt{1225}}{8}

y=\frac{-3 \pm 35}{8}

y=\frac{-3 +35}{8}                       y=\frac{-3 -35}{8}    

y=\frac{32}{8}                             y=\frac{-38}{8}

y= 4                                                           y =  −4.75

Since in the  question it is given that it is a positive integer

so  y = 4

substituting y=4 in eq (1) we get,

x= 3+4(4)

x= 3+16

x= 19

The sum of the two integers

=> x + y

=> 19+4

=>23

8 0
4 years ago
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