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OlgaM077 [116]
4 years ago
12

Which set of numbers is an arithmetic sequence?1, 5, 8, 13, ...2, 4, 8, 32, ...25, 21, 17, 13, ...81, 27, 9, 3, ...

Mathematics
2 answers:
kodGreya [7K]4 years ago
7 0

Answer:

The correct option is 3.

Step-by-step explanation:

The sequence is called an arithmetic sequence if the difference between every two consecutive terms are same.

In sequence 1, 5, 8, 13, ...

d_1=a_2-a_1=5-1=4

d_2=a_3-a_2=8-5=3

Since d_1\neq d_2, therefore the sequence 1, 5, 8, 13, ... is not an arithmetic sequence.

In sequence 2, 4, 8, 32,...

d_1=a_2-a_1=4-2=2

d_2=a_3-a_2=8-4=4

Since d_1\neq d_2, therefore the sequence 2, 4, 8, 32,... is not an arithmetic sequence.

In sequence 25, 21, 17, 13, ...

d_1=a_2-a_1=21-25=-4

d_2=a_3-a_2=17-21=-4

d_3=a_4-a_3=13-17=-4

Since this sequence has common difference of -4 therefore the sequence 25, 21, 17, 13, ... is an arithmetic sequence.

In sequence 81, 27, 9, 3, ...

d_1=a_2-a_1=27-81=-54

d_2=a_3-a_2=9-27=-18

Since d_1\neq d_2, therefore the sequence 81, 27, 9, 3, ... is not an arithmetic sequence.

Hence the correct option is 3.

masha68 [24]4 years ago
3 0
That would be    25,21,17,13...

this is arithmetic with a common difference of -4.
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4 years ago
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

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A = (350/13) and B = (400/-13)
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