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OlgaM077 [116]
3 years ago
12

Which set of numbers is an arithmetic sequence?1, 5, 8, 13, ...2, 4, 8, 32, ...25, 21, 17, 13, ...81, 27, 9, 3, ...

Mathematics
2 answers:
kodGreya [7K]3 years ago
7 0

Answer:

The correct option is 3.

Step-by-step explanation:

The sequence is called an arithmetic sequence if the difference between every two consecutive terms are same.

In sequence 1, 5, 8, 13, ...

d_1=a_2-a_1=5-1=4

d_2=a_3-a_2=8-5=3

Since d_1\neq d_2, therefore the sequence 1, 5, 8, 13, ... is not an arithmetic sequence.

In sequence 2, 4, 8, 32,...

d_1=a_2-a_1=4-2=2

d_2=a_3-a_2=8-4=4

Since d_1\neq d_2, therefore the sequence 2, 4, 8, 32,... is not an arithmetic sequence.

In sequence 25, 21, 17, 13, ...

d_1=a_2-a_1=21-25=-4

d_2=a_3-a_2=17-21=-4

d_3=a_4-a_3=13-17=-4

Since this sequence has common difference of -4 therefore the sequence 25, 21, 17, 13, ... is an arithmetic sequence.

In sequence 81, 27, 9, 3, ...

d_1=a_2-a_1=27-81=-54

d_2=a_3-a_2=9-27=-18

Since d_1\neq d_2, therefore the sequence 81, 27, 9, 3, ... is not an arithmetic sequence.

Hence the correct option is 3.

masha68 [24]3 years ago
3 0
That would be    25,21,17,13...

this is arithmetic with a common difference of -4.
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ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

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Dima020 [189]

Answer:

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nexus9112 [7]

Answer:

- 7, - 3, 1, 5

Step-by-step explanation:

Using the recursive rule and a₁ = - 7, then

a₂ = a₁ + 4 = - 7 + 4 = - 3

a₃ = a₂ + 4 = - 3 + 4 = 1

a₄ = a₃ + 4 = 1 + 4 = 5

The first four terms are - 7, - 3, 1, 5

4 0
3 years ago
PLS Help me Error Analysis
Maksim231197 [3]

we have

<u>Pieces of mail delivered in December by the US postal service</u>

7.14*10^{10}

<u>Pieces of mail delivered in January by the US postal service</u>

3.21*10^{10}

To find the total mail delivered for these two months, sum the two quantities

so

7.14*10^{10}+3.21*10^{10}=(7.14+3.21)*10^{10}\\=10.35*10^{10} \\=(1.035*10)*10^{10} \\=1.035*(10* 10^{10})\\=1.035*10^{(10+1)} \\= 1.035*10^{11}

therefore

the correct solution is 1.035*10^{11}

the error is in this part

10.35*10^{10}

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