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Illusion [34]
3 years ago
11

Given rectangular prism ABCD.

Mathematics
2 answers:
weqwewe [10]3 years ago
8 0

Answer:  Fourth and Fifth options are correct.

Step-by-step explanation:

Since we have given two points i.e. A, E, and J

We can see from the graph that

A, E, J are non coplanar and non collinear.

Coplanar means that all the points lie in the same plane.

Collinear means that all the points lie in the same line.

But A, E, and J are neither  in the same plane nor in the same line.

Hence, Fourth and Fifth options are correct.

Lana71 [14]3 years ago
4 0
B and d are tge answers
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Allen wants to have a mean of 90 on his math quizzes. So far, he has scored 86, 94, 88, 95, and 89. What is the least score that
viva [34]

Answer:

88

Step-by-step explanation:

\frac{86 + 94 + 88 + 95 + 89 + x}{6}  = 90

The mean would be the sum of all the math quiz grades divided by the number of quizzes taken.

Solve for x:

86 + 94 + 88 + 95 + 89 + x = 540

452 + x = 540

x = 88

Thus, Allen needs at least an 88 to obtain a mean of at least 90.

3 0
3 years ago
Whats the difference of 2 times d minus 3
Dmitriy789 [7]

Answer:

2(d - 3) is the equation. You cannot solve for d. You can only simplify it

7 0
3 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
A two digit number is chosen at random. funny the probability that the number is less than 20​
spin [16.1K]

Answer:

2/20

probability =1/10

3 0
3 years ago
Read 2 more answers
Write each number as a product of the GCF and another sum. Then use the Distributive Property to rewrite the sum. 45 + 30 = (15
Lorico [155]

Answer:

x=5/2

Step-by-step explanation:

Calculate, rewrite, remove the paretheses

Collect the like terms

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Then divide both sides

3 0
3 years ago
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