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igomit [66]
3 years ago
9

Can I get some help on this

Mathematics
1 answer:
nordsb [41]3 years ago
5 0
Answer: Choice C

The vertical asymptote at x = -4 tells us that -4 is not part of the domain. This only applies to 1/(x+4). If we plug in x = -4, we get...

f(x) = 1/(x+4)
f(-4) = 1/(-4+4)
f(-4) = 1/0
f(-4) = undefined; because of the division by zero error

The value x = -4 is allowed in the other answer choices.
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Find the smallest positive integer n such that the digit sum of n is divisible by 5, and the digit sum of n +1 is also divisible
alisha [4.7K]

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

6 0
2 years ago
The Big Telescope Company sells circular mirrors. Their largest mirrors have radii of 5 meters and their smallest mirrors have r
pogonyaev

Answer: 1:5

Step-by-step explanation:

Given: The cost of every mirror is proportional to the cube of the mirror's radius.

i.e. \dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{(\text{radii of smallest mirror}^3)}{\text{(radii of largest mirror)}^3}

Their largest mirrors have radii of 5 meters and their smallest mirrors have radii of 1 meter.

Then,

\dfrac{\text{Cost of smallest mirror}}{\text{Cost of  largest mirror}}=\dfrac{1^3}{(5)^3}=\dfrac{1}{125}

The ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors will be:

\dfrac{\text{Cost of 25 smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{25\times 1}{125}=\dfrac{1}{5}

Hence, the ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors = 1:5 .

5 0
2 years ago
How long does it takes for the stone to reach the river ?
ddd [48]
2.39 seconds I believe
4 0
3 years ago
What are equivalent expressions for 64x+80
ElenaW [278]
8(8x+10) could be used as a equivalent expression.
8 0
3 years ago
50% of what number is 8
Delvig [45]
We change 50% into 100%:\\ 50*2=100 \\ %. Make 8 out of 50:\frac{8}{50}=8÷50=0.16 Divide:100÷0.16=625. \\ 50 \ is \ 625 % of \ 8. Hoped I helped. :)
8 0
3 years ago
Read 2 more answers
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