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german
3 years ago
6

Sean went to the farmers Market and bought 3 3/4 pounds of beans at $11 and a pound and 10 1/2 pounds of flour at $0.55 per poun

d . I Sean paid for his purchase with a $100 bill how much change did she receive
Mathematics
1 answer:
mina [271]3 years ago
4 0
11 x 3 3/4 = 41 1/4 (41.25)

10 1/2 x 0.55 = 5.775

41.25 + 5.775 = 47.025

100 - 47.025 = $52.975 her change

Hope it helps!
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HI HELP ME W MATH PLSS!!
4vir4ik [10]

Answer:

a) 79.6

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Step-by-step explanation:

First, you have to do 318.4/4 to find the rate she goes in the duration of an hour. The rate is 79.6, which means she travels at a rate of 79.6 kilometers per hour.

Then, you have to find the distance she takes to travel in 5.5 hours, so you have to do 5.5*79.6 which is 437.8.

So, Hannah travels 437.8 kilometers in 5.5 hours.

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2 years ago
Solve for x:<br><br> 2(3x - 9) = 18x<br><br> x = -3/2<br><br> x = 3/2<br><br> x = 0<br><br> x = 6
Mila [183]
Remember yo can do anything to an equation as long as you do it to both sides

so
remember distributive property
a(b+c)=ab+ac

so first distribute
2(3x)+2(-9)=18x
6x-18=18x
minus 6x both sides
-18=12x
divide both sides by 12
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easier way is to first divide both sides by 2


x=-3/2
5 0
3 years ago
Read 2 more answers
Solve the two-step equation. 5.1 = –3x – 4.2
Tems11 [23]
5.1 = -3x - 4.2 

9.3=-3x 

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(1 point) Divide and simplify your answer.
VashaNatasha [74]

Answer:

18.174x

Step-by-step explanation:

5 0
2 years ago
Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

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\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

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