Answer:
6. 6x-21=33+9x 7. -15x=-5(3x+7) 8. 16x-19=113-6x 9. -19x-34=56-x 10. -6(4x+3)=6(4x-3)?
6. 6x-21 = 33 +9x
+21 + 21
6x = 54 + 9x
-9x -9x
-3x = 54
/3 /3
x = -18
7. -15x = -5(3x+7)
First multiply the -5 to the other numbers.
-15x = -15x - 35
0x = -35
7 is impossible I believe.
8. 16x-19 = 113-6x
+6 +6
22x - 19 = 113
+ 19 +19
22x = 132
/22 /22
x = 6
9. -19x - 34 = 56 - x
+19x +19x
-34 = 56 + 18x
-56 -56
-90 = 18x
/18 /18
x = -5
10. -6(4x+3) = 6[4x-3]
-24x - 18 = 24x - 18
+18 +18
-24x= 24x
x = 0, since only zero can make the equation true.
90+x+32=180
180-32=148
90+x=148
148-90=58
x=58
I hope this is correct
Answer:
25 +60
Step-by-step explanation: The first thing you need to do is realize that, this figure is a isosceles trapezoid due to the markings on each side.
So now we know both sides are 10.
We also know the the top two angles are congruent to each other and so are the bottom two angles due to the trapezoid being isosceles.
So the top two angles are 120 degrees and bottom two angles are 60 degrees.
It seems like we can't find the sides, let's try drawing two lines from each top angle all the way down to form two right triangles.
Wow, these two triangles are special right triangles in the form of
30 - 60 - 90 degrees.
shorter side = n
longer side = n
hypotenuse = 2n
So, 2n = 10
n = 5 for the short side
The bottom base is 4 + 5 + 5 = 10 + 4
The longer side is 5.
The area of trapezoid = (base1 + base2)/2 * height
= (4 + 10 + 4)/2 * 5 = (10 + 8)/2 * 5 = (5+4)*5 = 25 +60
So, 25 + 60 is our answer.
He has 3/4 package and plants 1/6 of seeds.
3/4 * 1/6 = 1/8
He divides the rest equally into 10 flowerpots. What is the rest? In order to know what "the rest" is, you must subtract 1/8 from 3/4. Find the common denominator of 4 and 8 which is 8. Multiple the numerator 3 * 2= 6 with a denominator of 8.
3/4 - 1/8 = 6/8 -1/8
= 5/8
5/8 is left to be divided equally into 10 flowerpots.
5/8 ÷ 10/1
= 5/8 * 1/10
= 5/80
= 1/16