Answer:
280
Step-by-step explanation:
2/3 * 42 = 28
28 * 10 = 280
Answer:
The answer to your question is 6.- B 7.- D
Step-by-step explanation:
Data
Parallelogram ACFG
6.-
m∠GAC = 112°
m∠ACF = ?
Process
These angles are supplementary, they measure the same.
∠GAC + ∠ACF = 180
-Substitution
112 + ∠ACF = 180°
-Solve for ∠ACF
∠ACF = 180° - 112°
-Result
∠ACF = 68°
7.-
m∠AGF = 2a + 10
m∠ACF = a + 20
The angles ∠GAC and ACF are equal, they measure the same.
∠GAC = ∠ACF
-Substitution
a + 20 = 2a + 10
-Solve for a
a - 2a = 10 - 20
-Result
-a = -10
a = 10
-Find ∠AGF
∠AGF = 2(10) + 10
20 + 10
= 30°
Answer:
what can i help u with
Step-by-step explanation:
The graph of x = |y| is as shown in the figure.
When we draw a vertical line, it intersects the graph at two points.
This means for the same value of x , we have two values of y.
Or in other words, for the same pre image, we have two images.
Hence it is not a function.
But for every value of x, we do have a value of y, hence it is a relation.
x = |y| is a relation but it is not a function
Answer: b = 2A - B
Step-by-step explanation:
2. A = 2 . 1/2 . h (B + b)
2A = h (B+b)
2A/= h/h . (B+b)
2A/h = B+b
2A - B = B - +b
b = 2A - B
The expression 4a^2c^2 - (a^2-b^2+c^2)^2 has to be factored.
4a^2c^2 - (a^2 - b^2 + c^2)^2
=> (2ac)^2 - (a^2 - b^2 + c^2)^2
=> (2ac - a^2 + b^2 - c^2)(2ac + a^2 - b^2 + c^2)
=> (b^2 - (a^2 - 2ac + c^2))((a^2 + 2ac + c^2) - b^2)
=> (b^2 - (a - c)^2)((a + c)^2 - b^2)
=> (b - a + c)(b + a - c)(a + b + c)(a - b + c)
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The factorized form of 4a^2c^2 - (a^2-b^2+c^2)^2 is (b - a + c)(b + a - c)(a + b + c)(a - b + c)</span>
