Ask question

Ask question

All categories

2 years ago

12

-2s(5st+3t) need help with problem

1 answer:

kipiarov [429]2 years ago

7 0

The answer to this problem is -10x^2t-6st to get this answer or this problem you must use the product rule formula x^a x^b=x^a=b

You might be interested in

You enter a relay race. To start, you must run 20 yards to Checkpoint A. You then must turn and run 12 yards to Checkpoint B. La

Anarel [89]

Distance to checkpoint A from starting line = 20 yards.

Then from A to B distance = 12 yards.

Let us take starting point C.

So, it would make a right triangle.

We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.

According to Pythagoras theorem:

$BC^2 = AB^2+AC^2$

$BC^2 = 12^2+20^2$

$BC^2 = 144 +400 = 544$

$BC= \sqrt{544}$

BC = 23.32.

<h3>Therefore, 23.32 yards is the distance from Checkpoint B to the starting line.</h3>

7 0

2 years ago

Read 2 more answers

Help plz and thank you.I don't know what am I suppose to do on this problems?!

lesya [120]

D= domain = farthest left and right
Domain = (3, infinite)
R = range = bottom to top
Range = (2,2)

3 0

2 years ago

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

2 years ago

Can someone please help me with this question ,

ollegr [7]

(x+6)(x+9) = 0
x+6 = 0 or x+9 = 0
x = -6 x = -9

Answer is A. -6 and -9

8 0

3 years ago

Sophie wants to determine if her seventh grade class wants to watch an action, horror, or drama movie. Which sampling method wou

lana66690 [7]

I think it would be B

7 0

3 years ago