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barxatty [35]
3 years ago
11

Graph the linear equation.find three points that solve the equation,then plot on the graph -3x++2y=11

Mathematics
1 answer:
Katarina [22]3 years ago
3 0

-3x+2y=11\qquad\text{add 3x to both sides}\\\\2y=3x+11\qquad\text{divide both sides by 2}\\\\y=\dfrac{3}{2}x+\dfrac{11}{2}\\\\for\ x=1\to y=\dfrac{3}{2}(1)+\dfrac{11}{2}=\dfrac{3}{2}+\dfrac{11}{2}=\dfrac{14}{2}=7\to(1,\ 7)\\\\for\ x=-3\to y=\dfrac{3}{2}(-3)+\dfrac{11}{2}=-\dfrac{9}{2}+\dfrac{11}{2}=\dfrac{2}{2}=1\to(-3,\ 1)\\\\for\ x=-5\to y=\dfrac{3}{2}(-5)+\dfrac{11}{2}=-\dfrac{15}{2}+\dfrac{11}{2}=-\dfrac{4}{2}=-2\to(-5,\ -2)

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Answer:

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Step-by-step explanation:

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The given vertices are:

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The sides will be:

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Let m1 be the slope of AB

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Hence,

The slopes of three sides of triangle are as follows:

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