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stellarik [79]
3 years ago
10

In ΔGHI, g = 2.7 inches, h = 6.6 inches and ∠I=58°. Find the area of ΔGHI, to the nearest 10th of a square inch.

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

7.5 inches

Step-by-step explanation:

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H(x) = 2x^2 =4; Find h(-10)
bogdanovich [222]

For this case we have the following function:

h (x) = 2x ^ 2 + 4

We must find the value of the function when x = -10

So, replacing we have:

h (-10) = 2 (-10) ^ 2 + 4\\h (-10) = 2 (100) +4\\h (-10) = 200 + 4\\h (-10) = 204

Thus, the value of the function is 204 when x = -10

Answer:

h (-10) = 204

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Which of the following gives a valid reason for using the given solution method to solve the system of equations shown?
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C

Step-by-step explanation:

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3 years ago
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Alex73 [517]

A. Perpendicular!

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8 0
3 years ago
Read 2 more answers
Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.
Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

\triangle ABC and \triangle DEC.

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and \angle B and \angle E are alternate angles \Rightarrow \angle B = \angle E.

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

\Rightarrow \angle ACB = \angle DCE

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. \angle B = \angle E

2. EC = CB

3. \angle ACB = \angle DCE

So, we can in see that in \triangle ABC and \triangle DEC, two angles are equal and side between them is also equal to each other.

Hence, proved that \triangle ABC \cong \triangle DEC.

8 0
3 years ago
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