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3 years ago

The diameter of Mercury is approximately 4.9×10^3 kilometers.

Mathematics

2 answers:

Aleks [24]3 years ago

7 0

Hi!

I'm quite sure the answer should be 24.

Mrrafil [7]3 years ago

6 0

2.4 I'm doing this for points by its correct put me as brainliest

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Evaluate the piecewise function at the indicated value from the domain: f(x)=[1/x, if x<-2 x^2, if x> with the equal sign

9966 [12]

The answer is B. I hope I've helped you.

4 0

3 years ago

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Andrea calls two truck rental companies to compare costs. Action trucks charges $80 for the day plus $0.22 per kilometer and tru

Amanda [17]

Answer:it will take 200 kilometers for the costs to be the same.

Step-by-step explanation:

Let x represent the number of kilometers that Andrea would have to drive for the total cost of renting from both companies to be the same.

Action trucks charges $80 for the day plus $0.22 per kilometer. It means that the total cost of x miles would be

80 + 0.22x - - - - - - - - - 1

Truck experts charges $100 for the day plus $0.12 per kilometer. It means that the total cost of x miles would be

100 + 0.12x - - - - - - - - - 2

Therefore, for the cost of renting from both companies to be the same,

80 + 0.22x = 100 + 0.12x

0.22x - 0.12x = 100 - 80

0.1x = 20

x = 20/0.1 = 200

4 0

3 years ago

Find the value of n. <br> 8034 × n = 80.34

liberstina [14]

N=1/100 this is the answer

8 0

3 years ago

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What is the quadratic factorization of <br>x^2+5x+6=?

dolphi86 [110]

Answer:

(x+3)(x+2)

Step-by-step explanation:

I can't explain it well, but I call it "reverse foil."

3 0

3 years ago

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A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

3 years ago