I need the answer to this problem. For math 3(5y+2)
1 answer:
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Answer:
The smallest integer is -4.
Step-by-step explanation:
Let the smallest integer be x.
Since the integers are all multiples of 4, they are
=> x, x+4, x+8, x+12 and x+16
=> x + x+4 + x+8 + x+12 + x+16 = 20
=> 5x + 40 = 20
Subtract 40 from both sides of the equation
5x +40 - 40 = 20 - 40
5x = -20
Divide both sides by the coefficient of x(which is 5)
x = -4
∴ the smallest integer is -4.
Hope this helps!!!