Answer:
X-bar chart
Explanation:
In industrial statistics, the X-bar chart is a type of Shewhart control chart that is used to monitor the arithmetic means of successive samples of constant size, n. The X-bar chart shows how the mean or average changes over time .For example, one might take a sample of 5 shafts from production every hour, measure the diameter of each, and then plot, for each sample, the average of the five diameter values on the chart. For the purposes of control limit calculation, the sample means are assumed to be normally distributed, an assumption justified by the Central Limit Theorem.
Answer:
gross profit under FIFO = $40,570 - $25,220 = $15,350
gross profit under LIFO = $40,570 - $26,340 = $14,230
gross profit under weighted average = $40,570 - $26,240 = $14,330
gross profit under specific id. = $40,570 - $26,070 = $14,500
Explanation:
sales revenue = (290 x $86.60) + (160 x $96.60) = $40,570
COGS under FIFO:
130 x $51.60 = $6,708
160 x $56.60 = $9,056
80 x $56.60 = $4,528
80 x $61,60 = $4,928
total COGS = $25,220
COGS under LIFO:
240 x $56.60 = $13,584
50 x $51.60 = $2,580
160 x $63.60 = $10,176
total COGS = $26,340
COGS under weighted average:
weighted average = [(130 x $51.60) + (240 x $56.60) + (100 x $61.60) + (180 x $63.60)] / 650 = $58.31
450 x $58.31 = $26,239.50 ≈ $26,240
COGS under specific method:
80 x $51.60 = $4,128
210 x $56.60 = $11,886
60 x $61.60 = $3,696
100 x $63,60 = $6,360
total COGS = $26,070
Answer:
Hours = 8000
Days = 46.78
Explanation:
The duration of this construction activity can be calculated as follows
DATA
No. of suits = 1000
Outlets to be installed = 12/suit
Standard productivity for outlet = 30mins
Fixtures to be installed = 6/suit
Standard productivity light fixture = 20mins
Working hours per day = 10 hours - 0.5 lunch break
Working hours per day = 9.5 hours
No. of crews = 18
Solution
Total time to fix = No.of suits x no. of installations x Standard time
Total time to fix = (1000 x 12 x 30mins ) + ( 1000 x 6 x 20mins)
Total time to fix = 480000 mins
Total time to fix = 480000/60mins = 8000 hours
Duration in days = Total time / (hrs per day x mo. of crews)
Duration in days = 8000 hours / (9.5 x 18)
Duration in days = 8000/171
Duration in days = 46.78 days
