The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
<em><u>x=9, y=12</u></em>
Step-by-step explanation:
-5x+4y=3
--------A
x=2y-15----------B
Putting the value of x from B in A
-5(2y-15) +4y=3
-10y+75+4y=3
-6y=3-72
-6y=-72
y=72/6= 12
Putting the value of y =12 in B
x= 2(12)-15
x= 24-15
x=9
The answer to this is 14. To find the hypotenuse from the short do 2S, and for Short to Long it is S Root 3.
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12 use a calculator i did it
Answer:
h=7ft
Step-by-step explanation:
sinФ=opposite/hypotenuse
sin45°=5/h
0.71=5/h
multiply via by h
0.71h=(5/h)h
h cancel h it remains 5
0.71h=5
divide through by 0.71
0.71h/0.71=5/0.71
h=7.04ft
h=7ft approximately
