if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
To rewrite this expression is first you must analyze first the equations and then proceed the the cancellations of values that are the same or having the same variables and the answer for this question is C tan x
Answer:
what is the question
Step-by-step explanation:
Answer:
![Var= 2.64](https://tex.z-dn.net/?f=Var%3D%202.64)
Step-by-step explanation:
Given
---Proportion
--- Sample Size
Required
Determine the variance
Variance (Var) is calculated as follows;
![Var= np(1 - p)](https://tex.z-dn.net/?f=Var%3D%20np%281%20-%20p%29)
Substitute values for n and p
![Var= 11 * 60\% * (1 - 60\%)](https://tex.z-dn.net/?f=Var%3D%2011%20%2A%2060%5C%25%20%2A%20%281%20-%2060%5C%25%29)
Convert percentage to decimal
![Var= 11 * 0.60 * (1 - 0.60)](https://tex.z-dn.net/?f=Var%3D%2011%20%2A%200.60%20%2A%20%281%20-%200.60%29)
![Var= 11 * 0.60 * 0.40](https://tex.z-dn.net/?f=Var%3D%2011%20%2A%200.60%20%2A%200.40)
![Var= 2.64](https://tex.z-dn.net/?f=Var%3D%202.64)
<em>Hence, the variance is 2.64</em>