Answer:
The required probability is 0.167
Step-by-step explanation:
Consider the provided information.
Let x be the number of breakdown per day.
A new automated production process averages 1.4 breakdowns per day.
λ=1.4
Probability of having three or more breakdowns during a day is:
![P(x\geq 3)=1-[f(0)+f(1)+f(2)]](https://tex.z-dn.net/?f=P%28x%5Cgeq%203%29%3D1-%5Bf%280%29%2Bf%281%29%2Bf%282%29%5D)
The Poisson probability function is: 
Therefore the required probability is:
![P(x\geq 3)=1-[\frac{\left(1.4^{0}e^{-1.4}\right)}{0!}+\frac{\left(1.4^{1}e^{-1.4}\right)}{1!}+\frac{\left(1.4^{2}e^{-1.4}\right)}{2!}]](https://tex.z-dn.net/?f=P%28x%5Cgeq%203%29%3D1-%5B%5Cfrac%7B%5Cleft%281.4%5E%7B0%7De%5E%7B-1.4%7D%5Cright%29%7D%7B0%21%7D%2B%5Cfrac%7B%5Cleft%281.4%5E%7B1%7De%5E%7B-1.4%7D%5Cright%29%7D%7B1%21%7D%2B%5Cfrac%7B%5Cleft%281.4%5E%7B2%7De%5E%7B-1.4%7D%5Cright%29%7D%7B2%21%7D%5D)
Hence, the required probability is 0.167
Answer:
length= 100 width=70
Step-by-step explanation:
The perimeter of a rectangular field is 340 yds.
The length is 30 yds longer than the width.
2(l + w) = 340
l + w = 170
w + 30 + w = 170
2w = 140
w = 70
Hence the dimensions:
Length: 100 yds.
Width: 70 yds.
Answer: If you substitute the x for 3, and multiply 4 times 3, you’ll get 12 and then you subtract 9 from 12 and then you’ll get 3. I’m pretty sure y=3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given given that
- Lower confidence interval = 7.1
- Upper confidence interval = 7.5
- As such, We are 95% confident that it's somewhere between 7.1 and 7.5 hours per night
Average value = LCI + UCI /2 = 7.1 + 7.5 / 2
= 7.3hours per night, so we are 95% confident that it's somewhere between 7.1 and 7.5 hours per night which is eventually 7.3hrs per night.
Answer:
To reconcile we need to match the checkbook balance with that of the bank balance :
Checkbook balance :
Initial checkbook balance = $43676.09
Note collected = $2160.00 , Bank Service Charge = $15
Final Checkbook Balance = Initial balance + Note collected - Service charge
= 43676.09 + 2160 - 15
= $45821.09
Bank balance :
Initial Bank balance = $49668.90
Outstanding deposits = $8474.44 , Outstanding checks = $12322.25
Final Bank Balance = Initial balance - Outstanding checks + Outstanding deposits
= 49668.90 - 12322.25 + 8474.44
= $45821.09
So, both the checkbook balance and the bank balance are equal.
