For this you will have to know how to add fractions. First of all i like to add the whole numbers together first, so 2+2+3= 7. so now what you have to do is add the fractions together. so 2/3 + 1/4 + 1/2 = ? you will have to find a common denominator for 3, 4, and 2; which is 12. Multiply each fraction by the needed number to get each denominator to 12. so 2/3 will be multiplied by 4, 1/4 will be multiplied by 3, and 1/2 will be multiplied by 6. The new equation and answer will be: 8/12 + 3/12 + 6/12 = 17/12. 17/12 as a mixed fraction is 1 5/12. now we add 1 5/12 and 7 to equal 8 5/12. and then you will have to subtract this from 10, using common denominators and such to get your final answer of 2 1/12. (sorry for the long spiel on how to do this question)
Answer:
4r ^2 +9r + 12
Step-by-step explanation:
Hope this helps! :)
There are 12 months in most years.
.. 23%/12 ≈ 1.91667%
_____
The answer shown in your picture is correct to 2 decimal places.
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater