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Firlakuza [10]
3 years ago
11

Assume that for a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. For someone who buys a set

of iour of these tires, what is the probability that all will last at least 30,000 miles? You be a suitable model in this case.
Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

The probability that all will last at least 30,000 miles is 0.3164.

Step-by-step explanation:

Consider the provided information.

For a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. Someone who buys a set of four of these tires,

That means the probability of not wearing out is 1-0.25 = 0.75

Now use the binomial distribution formula.

^nC_r (p^{n-r})(q^r)

Substitute p = 0.25, q=0.75, r=4 and n=4

^4C_4 (0.25)^{4-4}(0.75)^4

1 \times 0.75^4

0.3164

The probability that all will last at least 30,000 miles is 0.3164.

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Numbers are arranged by their place values. Place values give a quantity of value to a certain digit in a number. Given a number, the rightmost number is the ones place, followed by the tens place, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, hundred millions, as so on and so forth. The place value of a certain digit is 10 times bigger than its adjacent digit to the right.

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Answer:

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