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Firlakuza [10]
4 years ago
11

Assume that for a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. For someone who buys a set

of iour of these tires, what is the probability that all will last at least 30,000 miles? You be a suitable model in this case.
Mathematics
1 answer:
Hatshy [7]4 years ago
8 0

Answer:

The probability that all will last at least 30,000 miles is 0.3164.

Step-by-step explanation:

Consider the provided information.

For a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. Someone who buys a set of four of these tires,

That means the probability of not wearing out is 1-0.25 = 0.75

Now use the binomial distribution formula.

^nC_r (p^{n-r})(q^r)

Substitute p = 0.25, q=0.75, r=4 and n=4

^4C_4 (0.25)^{4-4}(0.75)^4

1 \times 0.75^4

0.3164

The probability that all will last at least 30,000 miles is 0.3164.

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Recatangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-2,1), B(3,1),C(3,4), and
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Answer: 15

Step-by-step explanation:

When you plot the points, it makes a rectangle. The length is 5 units and the height is 3 units. 5 times 3 is 15

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30,200 died in car accidents per year. How many deaths per day
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4 years ago
Given negative four and one sixth times negative three and fifteen hundredths, determine the product.
Contact [7]

The sum of the digits, B. thirteen and one eighth, is the product of the numerals.

<h3>How do you compute the value of the product?</h3>

According to the data, we are in the negative four hundred and one-sixth times the negative three hundred and fifteen-hundredths range.

This is going to be the product:

= (-4 1/6) × (-3 15/)

= - 4 1/6 × 3 3/20

= - 25/6 × -63/20

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2 years ago
Find the value of the test statistic z using . The claim is that the proportion of adults who smoked a cigarette in the past wee
kolezko [41]

Correct question is;

The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.35, and the sample statistics include n = 1168 subjects with 385 saying that they smoked a cigarette in the past week. Find the value of the test statistic

Answer:

Test statistic is z = -1.46

Step-by-step explanation:

Let's first of all define the hypotheses:

Null hypothesis:

H0: p = 0.35, i.e 35% in the sample of 1,168 adults have smoked cigarettes in the previous week.

Alternative hypothesis:

Ha: p < 0.35, i.e less than 35% in the sample of 1,168 adults have smoked cigarette in the previous week.

The sample size is, n = 1,168 while the number of adults who smoked in the previous week would be; x = 385

Therefore, the sample proportion of adults who smoked in the previous week would be calculated as;

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Formula for standard deviation is;

σ = √[p (1 – p)/n]

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σ = √0.0001947774

σ = 0.014

Formula for test statistic is;

z = (p^ - p)/σ

z = (0.3296 - 0.35)/0.014

z = - 1.46

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Alex_Xolod [135]
<span>A=1/2(a+b)h for h.

First, you need to get rid of 1/2, so divide both sides by 1/2.
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You can simplify the </span>A/(1/2) by multiplying by the reciprocal of 1/2, so 2/1.

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Now divide both sides by (a+b).

2A/(a+b) = h
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