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solong [7]
3 years ago
9

If G(x)=5x^2-8x, find g(a)

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

substitute a every place you see x

g(a) = 5a^2 -8a

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Find the area of a triangle bounded by the x-axis the line f(x)=5-5/3x and the line perpendicular to f(x)
viktelen [127]

Answer:

answer fx

Step-by-step explanation:

its fx because it works

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2 years ago
Celery is on sale at both Greg's market in the veggie emporium at Greg's market a 5 pound bag of celery cost $2.85 and a veggie
zhenek [66]
Gregs 285/5=57 Emporium 420/7=60
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3 years ago
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A stick 7 inches long is broken into two pieces, so that one piece is twice as long as the other one. How long are the two piece
marshall27 [118]

Hello from MrBillDoesMath!

Answer:

7/3 and 14/3 inches

Discussion:

Let P1 = "Piece 1" and "P2 = Piece 2", Then P2 = 2 * P1 and

P1 + P2 = 7       => as P2 = 2 P1

P1 + 2P1 = 7      =>

3P1 = 7             => divide both sides by 7

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7 0
3 years ago
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One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo
almond37 [142]

Answer:

(1) P(\bar X < 26 inches) = 0.0436

(2) P(27.5 inches < \bar X < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let \bar X = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

            Z = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean vertical  leap = 28 inches

            \sigma = standard deviation = 7 inches

            n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P(\bar X < 26 inches)

   P(\bar X < 26) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{26-28}{\frac{7}{\sqrt{36} } } ) = P(Z < -1.71) = 1 - P(Z \leq 1.71)

                                                 = 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < \bar X < 28.5 inches) = P(\bar X < 28.5 inches) - P(\bar X \leq 27.5 inches)

    P(\bar X < 28.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{28.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z < 0.36) = 0.64058 {using z table}                      

    P(\bar X \leq 27.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{27.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z \leq -0.36) = 1 - P(Z < 0.36)

                                                        = 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < \bar X < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0
3 years ago
35xy/7y simplified plz just simple fied it ;-; rip me i hate math mevr udnerstood it
ch4aika [34]
Its 7xy/1y I understand it its pretty easy
5 0
3 years ago
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