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Makovka662 [10]
3 years ago
6

The measure of one acute angle in a right triangle is 75.5°. What is the measure of the other acute angle in the triangle?

Mathematics
1 answer:
Serga [27]3 years ago
5 0
The answer is 14.5 degrees because and acute triangle is less than 90 degrees and you subtract 75.5 from 90 and you get 14.5. Hope I helped you
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A one year member ship to your local gym costs $539. there is an initial fee of $35. write an equation tou can use to fund out h
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$539 - $35 = $504

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Per month you pay $42.
4 0
2 years ago
Which expression is equivalent to -2 - 7?
SOVA2 [1]

Answer: -2 - (-7)

Step-by-step explanation: They both have the same outcome, 5. Which one is negative and one is positive. The last option is correct.

5 0
3 years ago
Read 2 more answers
Which is the constant term of the algebraic expression -2x2 + 17 -15x + 7xy?
Over [174]
17 is the constant term because it does not have any variables.
5 0
3 years ago
today's local newspaper lists 20 stocks of local interest. of those stocks ten increased five decreased and five remained unchan
coldgirl [10]

Answer:

P(x=2) = 0.2368

Step-by-step explanation:

given data

stocks of local interest N = 20

stocks increased K = 10

stocks decreased =  5

remained unchanged = 5

solution

we take here no of stock that are increased randomly n = 2

so here Hypergeometric random variable can take integer value

{max(0, n+k - N ), min(n,K) } = {0,2}

so here

P(x=2)

so

P(x=k)  = \frac{(^K_k)\times (^{N-K}_{n-k}) }{(^N_n)}      .......................1

P(x=2 ) = \frac{(^{10}_2)\times (^{20-10}_{2-2}) }{(^{20}_2)}    

solve it we get

P(x=2 ) = 0.236842

now we use excel function as

HYPGEOM.DIST (k,n,N.cumulative)   .....................2

so it will be

HYPGEOM.DIST (2,2,10,,false)

we get

HYPGEOM.DIST (2,2,10,,false)  = 0.236842

so

P(x=2) = 0.2368

4 0
3 years ago
If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe
lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = \frac{(length-covered-by-49-cars)}{Number-of-cars}

                          =\frac{528}{49}=10.78

Therefore, the average length of car is 10.78 feet

                 

6 0
3 years ago
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